Answer:
6 units
Step-by-step explanation:
Given: Points H and F lie on circle with center C. EG = 12, EC = 9 and ∠GEC = 90°.
To find: Length of GH.
Sol: EC = CH = 9 (Radius of the same circle are equal)
Now, GC = GH + CH
GC = GH + 9
Now In ΔEGC, using pythagoras theorem,
......(ΔEGC is a right triangle)
Now, Let GH = <em>x</em>
On rearranging,
So x = 6 and x = - 24
∵ x cannot be - 24 as it will not satisfy the property of right triangle.
Therefore, the length of line segment GH = 6 units. so, Option (D) is the correct answer.
Answer:
58 cm
Step-by-step explanation:
if both shapes are squares, then the perimeter must be divide by all 4 equal sides
36 / 4 = 9, so each side of the first shape is 9 cm
40 / 4 =10 , so each side of the second shape is 10 cm
by putting the shapes together two of the side seal 1 side of each shape but 10-9 is 1 so add all three sides of the rest of the shape,
so 9+ 9+ 9= 27, then the three side of the second shape,
so 10+ 10+ 10= 30, then that extra 1 cm of difference from the size difference when put together,
so 27+ 30+ 1= 58 cm
Answer:
If he deposited weekly, he would be depositing 9 dollars each week.
Step-by-step explanation:
Just thank me later and click the crown at the top of this answer if it helped ;)
Answer:
At least 4 numbers of information is needed
The four are highlighted below in the explanation section
Step-by-step explanation:
1. Given that the shape has four right angles and that all its sides are congruent then it's a quadrilateral
2. If two sides are consecutively congruent it is a quadrilateral shape
3. If a rhombus contains a right angle, then it’s a square shaped rhombus
4. If a quadrilateral is both a rectangle and a rhombus, then it’s a square
Speed
Riding speed = 9 mph
Driving speed = 27 mph
Time
If x hours is the time taken when riding, (x - 1/3) hours is the time taken when driving.
Distance in both instances is the same, D= Speed * time
Therefore,
9*x = 27(x-1/3)
9x = 27x - 27/2
9x = 27x - 9
(9-27)x = -9
-18x = -9
x = 9/18 = 1/2 hours
Distance, D = 1/2 *9 = 4.5 miles
