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2 years ago

Please help ! assignment is due at 11:59 pm !

Mathematics

1 answer:

I am Lyosha [343]2 years ago

6 0

Answer:

sorry hindi ako nakahabol

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What is the answer for this problem in the picture

DENIUS [597]

Answer:

The correct answer option is $= 8 x ^ 4 y z ^ 4 \sqrt{2yz}$ .

Step-by-step explanation:

We are given the following expression and we are to simplify it and determine whether which of the given expressions is equivalent to it, assuming $y\geq 0$ and $z\geq 0$ :

$\sqrt { 128 x ^ 8 y ^ 3 z ^ 9 }$

Breaking the terms to get:

$\sqrt { 128 x ^ 8 y ^ 3 z ^ 9 }$ $=8\sqrt{2yz} \times x^{8\times\frac{1}{2} } \times y^{2\times \frac{1}{2} } \times z^{8\times \frac{1}{2} }$

$= 8 x ^ 4 y z ^ 4 \sqrt{2yz}$

4 0

2 years ago

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James threw a flying disk from a height of 4 feet above the ground. The disk travels a horizontal distance of 30 feet before fal

Mrrafil [7]

Answer:

the domain represents the horizontal flying of the disk. The range of this function is [0, 7]. For this function, the range represents the flying disk's possible heights

5 0

2 years ago

Evaluate 12C3 Please show your work - Thank you!

dsp73

12C3 means nCr
You have 12 items of which you want to choose 3 and the order in which you choose them does not matter.

n! 12! 12! 479001600
---------- = -------- = ------- = ----------------- = 220
(r!(n-r)! 3!(12-3)! 3!(9!) 21177280

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2 years ago

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-x + 2y = 5 5x - 10y = 11 Solve for x and y they have to be equal

dlinn [17]

No solution

Hope this helps you

Mark brainliest please

6 0

1 year ago

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One of the questions on a survey asked adults if they used the internet at least occasionally. The results showed that 450 out o

earnstyle [38]

Answer: 0.9414

Step-by-step explanation:

Given : One of the questions on a survey asked adults if they used the internet at least occasionally.

450 out of 478 adults aged 18–29 answered Yes.

Then, the point estimate of the proportion of adults aged 18–29 who use the internet will be :-

$p=\dfrac{\text{No. of adults aged 18–29 answered Yes}}{\text{total adults aged 18–29 surveyed }}\\\\=\dfrac{450}{478}=0.9414$

Thus , a point estimate of the proportion of adults aged 18–29 who use the internet= 0.9414

3 0

2 years ago