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aleksklad [387]
3 years ago
11

17 Q Graph the inequality n a coordinate plane

Mathematics
1 answer:
aliina [53]3 years ago
7 0
The resultant graph is shown in the attached image.

Explanation:
Before we begin, remember that when we multiply by a negative sign, we flip the sign of the inequality
The given inequality is:
-y ≤ 3x - 5
We will multiply both sides by -1 to get a positive y vale. This will give us:
y ≥ -3x + 5

Now, to graph the inequality, we will first draw the line y = -3x + 5 and then shade the region having y values greater than the line. 
To know the region, you will simply use trial and error method for random points on the two sides of the line.

The final solution would be as shown in that attachment.

Hope this helps :)

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Talja [164]
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Read 2 more answers
<img src="https://tex.z-dn.net/?f=-6%20%2B%203x%20-%209x%5E%7B2%7D%3D-16" id="TexFormula1" title="-6 + 3x - 9x^{2}=-16" alt="-6
ehidna [41]

The solution of x in -6 + 3x - 9x^2 = -16 is x = \frac{3 \pm \sqrt{369}}{18}

<h3>How to solve the equation?</h3>

The equation is given as:

-6 + 3x - 9x^2 = -16

Add 16 to both sides

10 + 3x - 9x^2 = 0

Rewrite as:

9x^2 - 3x - 10 = 0

Solve for x using the quadratic formula

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

So, we have:

x = \frac{3 \pm \sqrt{(-3)^2 - 4 * 9 * -10}}{2 * 9}

Evaluate

x = \frac{3 \pm \sqrt{369}}{18}

Hence, the solution of x in -6 + 3x - 9x^2 = -16 is x = \frac{3 \pm \sqrt{369}}{18}

Read more about quadratic functions at:

brainly.com/question/1497716

#SPJ1

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2 years ago
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qaws [65]

Answer:(x+4)(x-6)

Step-by-step explanation:

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4 years ago
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