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aleksklad [387]
2 years ago
11

17 Q Graph the inequality n a coordinate plane

Mathematics
1 answer:
aliina [53]2 years ago
7 0
The resultant graph is shown in the attached image.

Explanation:
Before we begin, remember that when we multiply by a negative sign, we flip the sign of the inequality
The given inequality is:
-y ≤ 3x - 5
We will multiply both sides by -1 to get a positive y vale. This will give us:
y ≥ -3x + 5

Now, to graph the inequality, we will first draw the line y = -3x + 5 and then shade the region having y values greater than the line. 
To know the region, you will simply use trial and error method for random points on the two sides of the line.

The final solution would be as shown in that attachment.

Hope this helps :)

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Y = (2/3)x - 1<br> y = -x + 4
Vinil7 [7]
Are these two separate questions?
7 0
2 years ago
Helpp me pleasee.....
meriva

300; Since EF is the only segment not included in FHE, just subtract the 60 degrees there from 360 to get the sum of the rest of the circle

360-60 = 300

Hopefully this is right, i'm a little rusty on geometry

4 0
3 years ago
Simplify the expression below:
kifflom [539]

Answer:

C. -7x^2 - 28

Step-by-step explanation:

Firstly simplify the bracket before doing anything;

4x(3x - 7) = 12x^2 - 28x

then go back to the question and substitute the expression(12x^2 - 28x) on the bracket and then work out the question;

12x^2 - 28x -19x^2...then group the values with the same exponent of x,

(12x^2 - 19x^2) - 28x

; -7x^2 - 28x

6 0
3 years ago
Solve 5,4 = n/-0.9
PtichkaEL [24]

Step-by-step explanation:

5.4×-0.9=n

n=-4.86

(-4/5)/(1/3)=x

X=-2 2/5

8 0
3 years ago
Write the equation of the line that passes through (-6,0) and is parallel to the line y=5x-43
AVprozaik [17]

The equation of the line that passes through (-6,0) and is parallel to the line y = 5x - 43 in slope intercept is y = 5x + 30

<em><u>Solution:</u></em>

Given that line that passes through (-6, 0) and is parallel to the line y = 5x - 43

We have to find the equation of line

Let us first find slope of line having equation y = 5x - 43

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c  ------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing equation of line y = 5x - 43 with slope intercept form y = mx + c,

we get m = 5

Thus slope of given line is 5

We know that slopes of parallel lines are equal

Thus the slope of line parallel to given line is also 5

Now let us find equation of line having slope "5" and passes through (-6, 0)

Substitute m = 5 and (x, y) = (-6, 0) in eqn 1

y = mx + c

0 = 5(-6) + c

<h3>c = 30</h3>

<em><u>Thus the required equation is:</u></em>

Substitute c = 30 and m = 5 in eqn 1

y = 5x + 30

Thus the required equation of line is found

8 0
2 years ago
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