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Vikentia [17]
4 years ago
5

C + O2 = CO2

Chemistry
1 answer:
algol [13]4 years ago
5 0

So the product is CO2 and it says that it's mass is 44g. O2 is unknown, that means the mass of the products must equal the mass of the reactants. 44-12= 32g

Answer is 32

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Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

6 0
4 years ago
The acid dissociation constant, ka, of acetic acid is 1.8 x 10-5. what is the pka of this acid?
Orlov [11]

Answer:    approximately 4.74pKa is when you take the -log10 of your Ka. Therefore, taking the -log10(1.8*10-5), we get a value of approximately 4.74 for our pKa for acetic acid.

Explanation: hope this helps

4 0
3 years ago
What kind of bonding would exist between<br> sulfur and hydrogen?
Alexandra [31]

Answer:

nonpolar covalent

Explanation:

Comparing their electronegativities will help determine the type of bond. Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons. The difference in electronegativity (ΔEN)  is used to determine bond type. Hydrogen has an electronegativity of 2.20 and sulfur has 2.58. The difference is 0.38,so the electrons are shared in a nonpolar covalent bond.

5 0
3 years ago
What is the mass of a sample containing 8.53×10 to the 24th power formula units of magnesium phosphate?
Archy [21]

Answer:

Mass = 3732.62 g

Explanation:

Given data:

Number of formula units = 8.53×10²⁴

Mass of sample = ?

Solution:

1 mole of any substance contain 6.022×10²³ formula units.

8.53×10²⁴ formula units ×1 mol / 6.022×10²³ formula units

1.42×10¹ mol

14.2 mol

Mass of magnesium phosphate:

Mass = number of moles × molar mass

Mass = 14.2 mol × 262.86 g/mol

Mass = 3732.62 g

5 0
3 years ago
A box contains 104 gas molecules, 2500 of nitrogen and 7500 of argon in thermal equilibrium. The molecular weight of N2 is 28g/m
LekaFEV [45]

Answer : The temperature of this gas will be, 206.9 K

Explanation :

The expression for the kinetic energy per molecule of monoatomic gas (argon) is:

K.E_{argon}=n_{argon}\times \frac{3}{2}\times K_BT      ...........(1)

The expression for the kinetic energy per molecule of diatomic gas (nitrogen gas) is:

K.E_{nitrogen}=n_{nitrogen}\times \frac{5}{2}\times K_BT      .............(2)

The total kinetic energy of the molecule will be,

K.E_{Total}=K.E_{argon}+K.E_{nitrogen}

Now put all the expression in this, we get:

K.E_{Total}=(7500)\times \frac{3}{2}\times K_BT+(2500)\times \frac{5}{2}\times K_BT

T=\frac{K.E}{17500\times K_B}

Now put all the given values in this expression, we get:

T=\frac{5\times 10^{-17}J}{17500\times (1.381\times 10^{-23}J/K)}

T=206.9K

Therefore, the temperature of this gas will be, 206.9 K

8 0
4 years ago
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