Answer and Explanation:
The interphase is the previous step before mitosis occurs. The interphase is conformed of the G1, S, and G2 stages.
- During the G1 stage, it occurs a high intense biochemical activity. The cell duplicates its size, and the organelles and other molecules and cytoplasmatic structures duplicate too. Some structures, such as microtubules and actin filaments, are synthesized from zero. The endoplasmic reticulum increases in size and produces a membrane for the Golgi apparatus and vacuoles, lysosomes, and vesicles. During this stage, the pair of centrioles separate, and each centriole duplicates. Mitochondria and chloroplasts also replicate.
The stages S and G2 follow the G1. Once the whole interphase is completed, mitosis occurs.
- During the S stage occurs the DNI replication process. At this point, it also occurs the synthesis of histones and other associated proteins. This is the only stage where the DNI molecule is replicated.
- G2 stage is the final one before the cellular division. Here it begins the slow process of DNI condensation. Duplication of centrioles completes. Structures such as spindle fibers are assembled.
All the steps of GPCR signaling would be prevented in the presence of a beta-blocker drug.
<h3>What is Beta-blocker?</h3>
Beta-blocker may be defined as a kind of medication that chokes the activity of substances, such as adrenaline, on nerve cells and provokes blood vessels to relax and dilate.
Adrenergic receptors choke the attachment of catecholamine that is epinephrine to the G-protein. G-protein activates adenylyl cyclase which in turn activates protein kinase A.
But when the beta-blocker drug is subjected to this pathway, it blocks the attachment of the hormone to their receptors, hence none of the pathway or steps would be carried forward. This is because signaling is not initiated.
Therefore, all the steps of GPCR signaling would be prevented in the presence of a beta-blocker drug.
To learn more about GPCR signaling, refer to the link:
brainly.com/question/9882354
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Strong collagenous fibers, known as Sharpey’s fibers, connect the periosteum to the bone surface. This fiber extends to the bone’s circumferential (outer part) and interstitial lamellae (inner). It’s specifically made up of a fibrous layer (outside) and a cambium layer (inside).
Answer:
mass using E= mc^2 is = 0.007*(3E8)^2 = 6.3E14 Joules
Explanation:
hope this helps :)
i would say that the student is incorrect. temperature can flucuate but that doesnt indicate error
