Answer:
if repetition is allowed,
if repetition is not allowed.
Step-by-step explanation:
For the first case, we have a choice of 26 letters <em>each step of the way. </em>For each of the 26 letters we can pick for the first slot, we can pick 26 for the second, and for each of <em>those</em> 26, we can pick between 26 again for our third slot, and well, you get the idea. Each step, we're multiplying the number of possible passwords by 26, so for a four-letter password, that comes out to 26 × 26 × 26 × 26 =
possible passwords.
If repetition is <em>not </em>allowed, we're slowly going to deplete our supply of letters. We still get 26 to choose from for the first letter, but once we've picked it, we only have 25 for the second. Once we pick the second, we only have 24 for the third, and so on for the fourth. This gives us instead a pretty generous choice of 26 × 25 × 24 × 23 passwords.
There are eight, if I'm understanding the question correctly. 8 is in the ten thousands place, at least
Answer:
24 mm
Step-by-step explanation:
Since it is a right triangle, we can use Pythagorean theorem

where a and b are the legs, and c is the hypotenuse.
We know one of the legs is 10, and the hypotenuse is 26, so we can substitute 10 in for a, and 26 in for c.

Solve the exponents

Now, solve for b. To do this, get b by itself.
First, subtract 100 from both sides


Take the square root of both sides

b=24
So, the other leg is 24 mm
Answer:
Step-by-step explanation: