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BaLLatris [955]
2 years ago
14

Find the largest 4-digit number which is a perfect square.

Mathematics
2 answers:
pickupchik [31]2 years ago
6 0

Answer:

<em><u>To find the biggest 4-digit number which is a perfect square, we have to take the square of biggest 2-digit number. ∴ The biggest 4-digit number which is a perfect square = 9801.</u></em>

Step-by-step explanation:

<h2>mark as brainlest answer </h2>
Bond [772]2 years ago
5 0

Answer:

9801

Step-by-step explanation:

well we know 100 squared is the first 5 digit square number so it must be 99 squared, which is 9801

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A pharmacist has 40% and 80% iodine solutions on hand .How many liters of each iodine solutions will be required to produce 6 li
svetoff [14.1K]
So... let's change the concentration percentage to decimal format. .. so 40% is just 4/100 or 0.4  and so on.

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so... whatever "x" and "y" may be, we know the must add up to 6 liters.

and whatever 0.4x and 0.8y are, we also know, they must add up to a 3 of concentrated amount.

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solve for "x", to see how much of the 40% solution will be needed.

what about "y"?  well, y = 6 - x.
8 0
4 years ago
If 5 (3x - 7) = 20 what is 6x - 8​
garri49 [273]
You would have to solve for x the plug in the answer for c into the next equation to find your answer
6 0
3 years ago
Nickel-63 is a radioactive substance with a half-life of about 100 years. An artifact had
Marina CMI [18]

Answer:

see below

Step-by-step explanation:

The equation for half life is

n = no  e ^ (-kt)

Where no is the initial amount of a substance , k is the constant of decay and t is the time

no = 9.8

1/2 of that amount is 4.9 so n = 4.9 and t = 100 years

4.9 = 9.8 e^ (-k 100)

Divide each side by 9.8

1/2 = e ^ -100k

Take the natural log of each side

ln(1/2) = ln(e^(-100k))

ln(1/2) = -100k

Divide each side by -100

-ln(.5)/100 = k

Our equation in years is

n = 9.8  e ^ (ln.5)/100 t)

Approximating ln(.5)/100 =-.006931472

n = 9.8 e^(-.006931472 t)  when t is in years

Now changing to days

100 years = 100*365 days/year

36500 days

Substituting this in for t

4.9 = 9.8 e^ (-k 36500)

Take the natural log of each side

ln(1/2) = ln(e^(-36500k))

ln(1/2) = -36500k

Divide each side by -100

-ln(.5)/36500 = k

Our equation in years is

n = 9.8  e ^ (ln.5)/36500 d)

Approximating ln(.5)/365=-.00001899

n = 9.8 e^(-.00001899 d)  when d is in days

3 0
4 years ago
Read 2 more answers
. State the Fundamental Theorem of Arithmetic. Can two numbers have 18 as their HCF and 378
nadya68 [22]
I don’t now good luck!!!!!!!!!!!!!!!!
8 0
3 years ago
Read 2 more answers
PLZ HELP ASAP FIRST ANSWER GETS BRAINLEST WEN THERES TWO PPL WHO ANSWER QUESTION I CHOOSE WHO FIRST 1 WAS GETS IT N FIVE STAR N
Zigmanuir [339]

Answer:

£375

Step-by-step explanation:

Difference will be equal to the difference in VAT

(20% - 17.5%) of 15000

2.5% of 15000

2.5/100 × 15000

375

5 0
4 years ago
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