The solution to the equation is p = 1/3 and q = undefined
<h3>How to solve the equation?</h3>
The equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
The best way to solve the above equation is by the use of a graphing calculator i.e. graphically
However, it can be solved algebraically too (to some extent)
Recall that the equation is given as:
p^2 - 2qp + 1/q = (p - 1/3)
Split the equation
So, we have
p^2 - 2qp + 1/q = 0
p - 1/3 = 0
Solve for p in p - 1/3 = 0
p = 1/3
Substitute p = 1/3 in p^2 - 2qp + 1/q = 0
So, we have
(1/3)^2 - 2q(1/3) + 1/q = 0
This gives
1/9 - 2/3q + 1/q = 0
This gives
2/3q + 1/q = -1/9
Multiply though by q
So, we have
2/3q^2 + 1 = -1/9q
Multiply through by 9
6q^2 + 9 = -q
So, we have
6q^2 + q + 9 = 0
Using the graphing calculator, we have
q = undefined
Hence. the solution to the equation is p = 1/3 and q = undefined
Read more about equations at:
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4.) (the next prime function)
2x2x3x2
2x2x3x2x2
2x2x3x2x2x2
Answer:
3.
7.608
Step-by-step explanation:
An irrational number is any number which can't be written as a fraction this way. For example, pi and the square root of two cannot be expressed as a fraction of two whole numbers, so they are both irrational.
if we make the respective accounts in the first and second problem we will see that they are irrational numbers
the fourth is a periodic number, which falls within the irrational
the only rational is the third
Hey number 8. Be super careful, less than always look at that it should be 5n-3
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