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Travka [436]
3 years ago
13

The current in the circuit shown is 2.0 A.

Mathematics
2 answers:
Rama09 [41]3 years ago
8 0

Answer:

its A

Step-by-step explanation:

Sphinxa [80]3 years ago
3 0
The answer A thank me later
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What is the sum of the expressions for n=-2n=−2 and m=5m=5 ?
Liula [17]

Answer:

- 43

Step-by-step explanation:

Expression: (3m+2n−6) and (−4−6m+7n)

n= -2 and m=5

Before inserting the values, let's add both expressions.

(3m+2n−6)  + (−4−6m+7n)

3m+2n−6   −4 − 6m + 7n

-3m + 9n - 10

Inserting the values;

-3(5) + 9(-2) - 10

-15 - 18 -10

- 43

6 0
3 years ago
Simplify the following question
fiasKO [112]

Answer:

<em>−  2sin(b) / cos(2b)</em>

​

Step-by-step explanation:

DIFFERENTIATE W.R.T. B is a different method entirely

We simply add together the numerators and set with 2cos

then keep this number and add to sinb and square it.

then repeat initial 2 + cosb ^2 but instead of multiplying its add.

Then set the whole division to -sin (2b) squared then +1

<em> −  2cos(b)(3(sin(b))^2+(cos(b))^2)  /  −(sin(2b)) ^2 +1  </em>

​

 

5 0
2 years ago
-(y + 2) + 8 = 3<br> I’m so confused on this, please send help
Hoochie [10]

Don't be worried friend :)

-(y + 2) + 8 = 3

=> -(y + 2) = -5

=> y + 2 = 5

=> y = 3

7 0
3 years ago
Find the length of the arc of the circular helix with vector equation r(t) = 2 cos t i + 2 sin t j + tk from the point (2, 0, 0)
USPshnik [31]

\vec r(t)=2\cos t\,\vec\imath+2\sin t\,\vec\jmath+t\,\vec k

\implies\vec r'(t)=-2\sin t\,\vec\imath+2\cos t\,\vec\jmath+\vec k

\implies\|\vec r'(t)\|=\sqrt{(-2\sin t)^2+(2\cos t)^2+1^2}=\sqrt5

Then the length of the arc is

\displaystyle\int_0^{2\pi}\|\vec r'(t)\|\,\mathrm dt=\sqrt5\int_0^{2\pi}\mathrm dt=2\sqrt5\,\pi

4 0
3 years ago
(2r)^5 typed in expanded form.
liberstina [14]
The answer is 2^5r^5
,.. ....
4 0
3 years ago
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