It will travel 7.5 cm a revolution and 7.5 x 3 wound = your answer i believe
lol i hate geomatry
Answer:
![\boxed{w=-10}](https://tex.z-dn.net/?f=%5Cboxed%7Bw%3D-10%7D)
The answer have negative sign.
Step-by-step explanation:
<em>Subtract by 6 both sides of equation.</em>
![-4w+6-6=46-6](https://tex.z-dn.net/?f=-4w%2B6-6%3D46-6)
<em>Simplify.</em>
![46-6=40](https://tex.z-dn.net/?f=46-6%3D40)
![-4w=40](https://tex.z-dn.net/?f=-4w%3D40)
<em>Divide by -4 both sides of equation.</em>
![\frac{-4w}{-4}=\frac{40}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B-4w%7D%7B-4%7D%3D%5Cfrac%7B40%7D%7B4%7D)
<em>Simplify to find the answer.</em>
![40\div-4=-10](https://tex.z-dn.net/?f=40%5Cdiv-4%3D-10)
<em>
, is the correct answer</em>
The function is
![h(t) = -16t^2 + 80t + 224](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E2%20%2B%2080t%20%2B%20224)
, and according to the description of the function in the problem statement, we have the following:
at t=0 after being thrown (that is, at initial time), the height of the ball is calculated by h(0) as follows:
![h(0) = -16(0)^2 + 80(0) + 224=0+0+224=224](https://tex.z-dn.net/?f=h%280%29%20%3D%20-16%280%29%5E2%20%2B%2080%280%29%20%2B%20224%3D0%2B0%2B224%3D224)
(ft), which is the initial height, as expected.
At t=1 (sec), the height would be
![h(1) = -16(1)^2 + 80(1) + 224=-16+80+224=288](https://tex.z-dn.net/?f=h%281%29%20%3D%20-16%281%29%5E2%20%2B%2080%281%29%20%2B%20224%3D-16%2B80%2B224%3D288)
.
etc.
The path is parabolic, as we know by seeing that the function is a quadratic polynomial function. This function has been given in factored form as well. From that we can see that the zeros of the function are t=7 and t=-2.
This means that at t=7 sec, the height h is 0, which means that the ball has hit the ground. t=-2 has no significance in the context of our problem so we just neglect it.
Answer: B) 7 sec
Well we need to see the figure mate. In order to compare it