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Rashid [163]
2 years ago
10

Which function below is the inverse of f(x) = The quantity of four x minus three, over two.?

Mathematics
1 answer:
Genrish500 [490]2 years ago
5 0
y = \frac{4x-3}{2}  \\ 2y=4x-3 \\ 4x=2y+3 \\ x= \frac{2y+3}{4}  \\  f^{-1} (x)=\frac{2x+3}{4}
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Can someone help me with this question.
Digiron [165]

Answer:

C

Step-by-step explanation:

A function means that a graph cannot have repeating x values, so to test if something is a function we do the horizontal line test. You simply draw a vertical line and if the graph touches it twice it is not a function.

4 0
3 years ago
A shoe store uses a 60​% markup for all of the shoes it sells. What would be the selling price of a pair of shoes that has a who
zhenek [66]

Answer:

I think it would be $81.60

Step-by-step explanation:

6 0
3 years ago
Let​ T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear​ transformation, and
Klio2033 [76]

Answer:

\{T(v_1), T(v_2), T(v_3)\} is linearly dependent set.

Step-by-step explanation:

Given:  \{v_1,v_2,v_3\} is a linearly dependent set in set of real numbers R

To show: the set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

Solution:

If \{v_1,v_2,v_3,...,v_n\} is a set of linearly dependent vectors then there exists atleast one k_i:i=1,2,3,...,n such that k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0

Consider k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

A linear transformation T: U→V satisfies the following properties:

1. T(u_1+u_2)=T(u_1)+T(u_2)

2. T(au)=aT(u)

Here, u,u_1,u_2∈ U

As T is a linear transformation,

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\

As \{v_1,v_2,v_3\} is a linearly dependent set,

k_1v_1+k_2v_2+k_3v_3=0 for some k_i\neq 0:i=1,2,3

So, for some k_i\neq 0:i=1,2,3

k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0

Therefore, set \{T(v_1), T(v_2), T(v_3)\} is linearly dependent.

6 0
3 years ago
WILL MARK BRAINLIEST PLS HELPPPPPP
Viktor [21]

Answer:

This is the graph of y = 0.4x

4 0
2 years ago
What is this question?? (needing help)
Free_Kalibri [48]

468 x 0.001 = 0.468

46.8 x 0.1 = 4.68

4.68 x 10^3 = 4680

0.468 x 10^2 = 46.8

Hope this helps!

5 0
3 years ago
Read 2 more answers
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