Answer:
The usual size of the container is 15 ounces.
Step-by-step explanation:
Consider the provided information.
A protein mix claims to contain a bonus of 20% more mix than the usual size container.
Let the usual size of the container was x ounces.
They increase 20% of usual size and the bonus size is 18 ounces.
Therefore, the new size should be:

(∴20%=
=0.20)



Hence, the usual size of the container is 15 ounces.
Answer:
29
you have to solve the brackets first(6-3=3)
Then solve the division (4/2=2)
lastly the addition (5+4=9)
so we have 9×3=27
27+2=29.
Answer:
A = 58.7 degrees
B = 66.9 degrees
C = 34.1 degrees
Step-by-step explanation:
<u><em>For <A:</em></u>
Tan A = 
Tan A = 
Tan A = 1.6
A = 
A = 58.7 degrees
<u>For <B:</u>
Sin B = 
Sin B = 
Sin B = 0.92
B = 
B = 66.9 degrees
<em><u>For <C:</u></em>
Sin C = 
Sin C = 
Sin C = 0.56
C = 
C = 34.1 degrees
Answer:
1.a=2
2. C x=2 and x=-3
Step-by-step explanation:
The standard form for the quadratic function is
ax^2 +bx+c
so we need to rewrite the function to be in this form
2x^2 -10 = 7x
Subtract 7x from each side
2x^2 -7x-10 = 7x-7x
2x^2 -7x-10 = 0
a =2, b= -7 c=-10
2. The quadratic formula is
-b ± sqrt(b^2 -4ac)
----------------------------
2a
2x^2 + 2x=12
Lest get the equation in proper form
2x^2 + 2x-12 = 12-12
2x^2 +2x-12 =0
a=2 b=2 c=-12
Lets substitute what we know
-2 ± sqrt(2^2 -4(2)(-12))
----------------------------
2(2)
-2 ± sqrt(4+96)
----------------------------
2(2)
-2 ± sqrt(100)
----------------------------
4
-2 ± 10
----------------------------
4
-2 + 10 -2-10
----------- and --------------
4 4
8/4 and -12/4
2 and -3
Answer:
10.3cm
Step-by-step explanation:
h=A
b=131.84
12.8≈10.3cm