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3241004551 [841]
3 years ago
9

john enlarges a square by using a scale of 8:1, how much greater is the area of the enlarged square in units squared than the or

iginal square?
Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

i would say by 7 not 100% sure sorry if it doesnt help :( im trying

Step-by-step explanation:

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Which of the point-slope equations below are correct for the line that passes through points (-2, -2) and (2, 1)?
Ne4ueva [31]
Find slope first:
m =y2-y1/x2-x1
m = 1--2/2--2
m = 3/4

Select a point, insert your slope, & put it into point slope form:
y-y1 =m(x-x1)

Your final answers are:

y-1=3/4(x-2)
OR
y+2 =3/4(x+2)
8 0
3 years ago
-4y+5x=17 the point (x,-3) is a solution to the equation shown. What is the value of x
MrMuchimi

Answer:

x = 1

Step-by-step explanation:

-4v+5x=17 give that (x,-3) is the solution

so x coordinate is = x (unknown)

y coordinate is = -3

substitute the value of y in -4y+5x=17

therefore

-4(-3)+5x=17

12+5x=17

5x=17-12

5x=5

x=5/5

x=1

6 0
3 years ago
Read 2 more answers
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
4 years ago
Find the length of a picture frame whose width is 3 inches and whose proportions are the same as a 9-inch wide by 15-inch long p
Artist 52 [7]

Answer:

The length is 5 inches.

Step-by-step explanation:

9/3=15/?

If you divide 9 by 3, you get 3 if you compare things you have to do the same on the other 'side'. So you do 15 divided by 3, the answer is 5.

7 0
3 years ago
Jaquelyn‘s earnings m are a function of the number of lawns n she mows at a rate of $12 per lawn
nadya68 [22]
Your function is

m = 12n
or
m(n) = 12n 
7 0
4 years ago
Read 2 more answers
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