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Alisiya [41]
3 years ago
15

Using the order of operations , what should be done first to evaluate 12÷(-6)(3)+(-2)​

Mathematics
1 answer:
8090 [49]3 years ago
3 0

Answer:

Step-by-step explanation:

12/-6

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Find the length of side LK. ​
olya-2409 [2.1K]

Answer:

7 is the answer

Step-by-step explanation:

4 0
3 years ago
Solve the equation for all real solutions in simplest form.<br> z^2 - 12z +9= -3
Mars2501 [29]

Answer:

Solving the equation for all real solutions in simplest form.

z^2 - 12z +9= -3 we get \mathbf{z=10.9\: or\: z=1.1}

Step-by-step explanation:

We need to solve the equation for all real solutions in simplest form.

z^2 - 12z +9= -3

First simplifying the equation:

z^2 - 12z +9+3= -3+3\\z^2 - 12z +12= 0

Now, we can solve the equation using quadratic formula:

z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

we have a = 1, b=-12 and c=12

Putting values in formula and finding values of x

z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\z=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(12)}}{2(1)}\\z=\frac{12\pm\sqrt{144-48}}{2}\\z=\frac{12\pm\sqrt{96}}{2}\\z=\frac{12\pm9.8}{2}\\z=\frac{12+9.8}{2}\:or\:z=\frac{12-9.8}{2}\\z=10.9\:or\:z=1.1

So, we get value of z: z=10.9 or z=1.1

Solving the equation for all real solutions in simplest form.

z^2 - 12z +9= -3 we get \mathbf{z=10.9\: or\: z=1.1}

3 0
3 years ago
What are the values of a, b, and c in the quadratic equation 0 =1/2x^2-3x-2
bonufazy [111]

Answer:

<u>The correct answer is 2. a = 1/2, b = - 3, c = -2</u>

Step-by-step explanation:

1. Let's review the information provided for an answering the question correctly:

0 =1/2x^2- 3x- 2

0 = 1/2x² - 3x - 2

2. Let's find the values for a, b and c.

According to the quadratic equation, we have:

a = 1/2

b = - 3

c = - 2

<u>The correct answer is 2. a = 1/2, b = - 3, c = -2</u>

7 0
4 years ago
HIII Brainly People I need help with those math problems I HATE MATH so if you could help that me that would be nice. :)
horrorfan [7]

Answer:

First off  

Step-by-step explanation:

8 0
3 years ago
What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?
babunello [35]

Answer:

x + 6

Step-by-step explanation:

Edit:

A moderator mentioned my answer had a mistake: turned out the question posted was incomplete. The complete question should read:

"

What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?

x – 6

x – 3

x + 1

x + 6

"

As shown in the same graph, f(x) cross the x-axis at x = -6, -3 and 0.

When a polynomial crosses the x-axis at x = a, (x - a) must be a factor.

So (x + 6), (x + 3) and x are factors of f(x).

Of the options, the correct answer is x + 6.

The complete question with verified answer is here: brainly.com/question/3875529

6 0
2 years ago
Read 2 more answers
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