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Paladinen [302]
3 years ago
14

What is the slope of the line that passes through the pair of points? (5,2) and (7,8) the answers are 2/3,-2/3,3/2 or -3/2

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0
Answer:  The slope is:  "3" ; which does not appear among the                                   answer choices given.
______________________________________________

The slope, "m" is calculated as follows:
___________________________________
Given two coordinates on a line; 

m = (y₂ − y₁) / (x₂ − x₁) ;
__________________________________________

We are given the following 2 (TWO) coordinates:
__________________________________________
 1)  (5,2) ; which is:  (x₁ ,y₁) ;  so x₁ = 5 ; y₁ = 2 ; AND:
 
 2)  (7,8);  which is:  (x₂ ,y₂) ;  so x₂ = 7; y₂ = 8 ;
_____________________________________________
So;  m = (y₂ − y₁) / (x₂ − x₁) = (8−2) /.(7−5) = 6/2 = 3 .

m = 3.  The slope is: 3 ; which does not appear among the answer choices given.
______________________________________________
Alternately,
______________________________________________
We are given the following 2 (TWO) coordinates:
__________________________________________
 1)  (7,8) ; which is:  (x₁ ,y₁) ;  so x₁ = 7 ; y₁ = 8 ; AND:
 
 2)  (5,2);  which is:  (x₂ ,y₂) ;  so x₂ = 5; y₂ = 2 ;
______________________________________________
So;  m = (y₂ − y₁) / (x₂ − x₁) = (2−8) / (5−7) = -6/-2 = 3 .

m = 3.  The slope is 3 ; which does not appear among the answer choices given.
________________________________________________
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Step-by-step explanation:

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3 years ago
Is three eighths equal to two sixths
LuckyWell [14K]
You can write it out: 3/8 and 2/6. You can simplify 2/6 to 1/3. So 3/8 and 1/3. Those 2 fractions are not the same. 3/8 is bigger.
Sources: my brain and scratch paper
Hope this helps! :-)
8 0
3 years ago
Find the centroid of the thin plate bounded by the graphs of the functions g(x )= x^2 (x - 1) + 2 and f(x) = x^2 + 2 with delta
lawyer [7]

Answer:

X = 6/5

Y = 176/56

Step-by-step explanation:

Given

g(x) = x²(x-1)+2

f(x) =x²+2

We find the limits as follows:  x²(x-1)+2 = x²+2

⇒ x²(x - 1 - 1) = x²(x - 2) = 0

⇒  x₁ = 0  and x₂ = 2

If x = 1

g(1) = (1)²(1 - 1) + 2 = 2

f(x) = (1)² + 2 = 3

then

f(x) > g(x)

We get the Area

A = ∫(f(x)- g(x))dx =∫((x²+2)-( x²(x-1)+2))dx =  ∫x²(2-x)dx = (2/3)x³-(1/4)x⁴+C

A = (16/3) - 4 = 4/3

X = (1/A)∫(x(f(x)- g(x)))dx = (3/4)∫(x³(2-x))dx = (3/4) ((1/2)x⁴-(1/5)x⁵)+C

X = (3/4) ((1/2)(2)⁴-(1/5)(2)⁵) = (3/4)(8-32/5) = (3/4)(8/5) = 6/5

Y = (1/(2A))∫((f(x))²-(g(x))²)dx = (3/8)∫((x²+2)²-( x²(x-1)+2)²)dx

Y = (3/8)∫(-x⁶+2x⁵-4x³+8x²)dx = (3/8)(-(1/7)x⁷+(1/3)x⁶-x⁴+(8/3)x³+C)

Y = (3/8)(-(1/7)(2)⁷+(1/3)(2)⁶-(2)⁴+(8/3)(2)³) = (3/8)(176/21) = 176/56

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3 years ago
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