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olya-2409 [2.1K]
3 years ago
7

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..........................................

Mathematics
1 answer:
Ahat [919]3 years ago
4 0
The answer to this would be 7 1/2.
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A chemical factory has 2 cylindrical chemical tanks, one containing Chemical X and the other containing Chemical Y. The tank con
Mashutka [201]
The tank with Chemical X "takes up" a space of 25ft³.  Ordinarily we think of something "taking up" space as being area or surface area; however, area is a square measurement, and this is cubic; this must be volume.  The volume of the tank with Chemical X is 1.5 times the volume of the tank containing Chemical Y; setting this up in an equation we would have
25 = 1.5<em>V</em>
We would divide both sides by 1.5 to get the volume of the tank containing Chemical Y:
\frac{25}{1.5}=\frac{1.5V}{1.5} \\16 \frac{2}{3}=V
To find the volume of a cylinder, we find the base area and multiply by the height.  We know the volume and we know the base area, so our equation to find the height of the tank containing Chemical Y would look like:
16 \frac{2}{3}=3.2h \\ 16 \frac{2}{3}=3 \frac {2}{10}h
We would now divide both sides by 3 2/10:
\frac{16 \frac{2}{3}}{3 \frac{2}{10}}= \frac{3 \frac{2}{10}h}{3 \frac{2}{10}}
This is the same as:
\frac{\frac{50}{3}}{\frac{32}{10}}=h \\ \\ \frac{50}{3}* \frac{10}{32}=h \\ \\ \frac{500}{96}
So the height of the tank containing Chemical Y is 500/96 = 5 5/24 feet.
8 0
3 years ago
In Mr. Romero's class is 25 students, 13 of them participate in school sports. What percent of students participate in school sp
never [62]

Just do this to find the percentage:

13/25 * 100%

= 0.52 *100%

= 52%

7 0
4 years ago
3p-9=4p<br> What is the value of p?
gtnhenbr [62]
The answer is -9 do you get it?

4 0
4 years ago
Read 2 more answers
I need help on number 3 please.
insens350 [35]
The correct answer is b
6 0
4 years ago
An equation is given. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places w
Rina8888 [55]

Answer:

a) The general solution   θ = nπ±π/6

The all solutions are  - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b)   The solutions in the interval [ 0,2π)

                            θ =  - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

Step-by-step explanation:

<u><em>Step( i)</em></u>:-

Given an equation 2 cos (2θ)-1 =0

                               2 cos (2θ) = 1

                                cos(2θ) = 1/2

                                cos(2θ) = cos (π/3)

<em>Step(ii):-</em>

<em>a) </em>

The general solution of  cos θ = cos ∝ is given by

                                              θ = 2nπ±∝

The general solution of  cos(2θ) = cos (π/3) is

                                               2θ = 2nπ±π/3

                                                θ = nπ±π/6

Put n=0          θ =  ±π/6

Put n =1          θ = π±π/6

                       θ = π-π/6 = 5π/6

                        θ = π+π/6 = 7π/6

put n =2

                        θ = 2π±π/6  

                         θ = 2π-π/6 = 11π/6

                        θ = 2π+π/6 = 13π/6

   

The all solutions are  - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b)

        The solutions in the interval [ 0,2π)

                            θ =  - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

<u><em>Final answer</em></u>:-

a)

The all solutions are  - π/6 ,π/6 ,5π/6 ,7π/6 ,11π/6 ,13π/6 ...…

b)

The solutions in the interval [ 0,2π)

                            θ =  - π/6 ,π/6 , 5π/6 , 7π/6 , 11π/6

             

                                               

                                         

8 0
4 years ago
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