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tiny-mole [99]
4 years ago
15

Linda and Colleen both leave the library at the same time, but in opposite direction. If Colleen travels 8mph faster than Linda

and after 8 hours they are 176 miles apart, how fast is each traveling?
Mathematics
1 answer:
pshichka [43]4 years ago
8 0
X - Linda's speed
(x+8 )- Colleen's speed

8x - Linda's distance for 8 h
8(x+8) = 8x+64  - Colleen's distance for 8 h

8x + 8x + 64 = 176 - distance between Colleen and Linda after 8 h


8x + 8x + 64 = 176 
16x +64 = 176
16x = 176 - 64
16x = 112
x= 7 mph Linda's speed
x+8
= 7+8 = 15 mph Colleen's speed
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grin007 [14]
Given:
Principal: 19,200
term: 5 years

a) Interest compounded annually:
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8 0
4 years ago
It takes 16 minutes for 9 people to paint 8 walls . How many minutes does it take for 4 people to paint 6 walls?
Soloha48 [4]

Answer:

27 minutes to complete the painting of 4 walls

Step-by-step explanation:

since 16m with 9p --> 8 walls

x minutes with 4p --> 6 walls?

let x= minutes

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x= 6 divided by (8/144)

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4 0
3 years ago
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5. The distance between two given points (5,2) and (x,5) is 5 units. Find the possible values of x. *​
kirza4 [7]
<h3>Answers:  x = 1 and x = 9</h3>

============================================================

Explanation:

We'll use the distance formula here. Rather than compute the distance d based on two points given, we'll go in reverse to use the given distance d to find what the coordinate must be to satisfy the conditions.

We're given that d = 5

The first point is (x_1,y_1) = (5,2) and the second point has coordinates of (x_2,y_2) = (x,5) where x is some real number.

We'll plug all this into the distance formula and solve for x.

d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\5 = \sqrt{(5-x)^2+(2-5)^2}\\\\5 = \sqrt{(5-x)^2+(-3)^2}\\\\5 = \sqrt{(5-x)^2+9}\\\\\sqrt{(5-x)^2+9} = 5\\\\(5-x)^2+9 = 5^2\\\\(5-x)^2+9 = 25\\\\(5-x)^2 = 25-9\\\\(5-x)^2 = 16\\\\5-x = \pm\sqrt{16}\\\\5-x = 4 \ \text{ or } \ 5-x = -4\\\\-x = 4-5 \ \text{ or } \ -x = -4-5\\\\-x = -1 \ \text{ or } \ -x = -9\\\\x = 1 \ \text{ or } \ x = 9\\\\

This means that if we had these three points

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Then segments AB and AC are each 5 units long.

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Hey there!

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