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aliya0001 [1]
3 years ago
10

Help me, please! (doing this for my Lil sister 6th-grade mathematics)

Mathematics
2 answers:
dangina [55]3 years ago
5 0
The answer to your question is B
Oliga [24]3 years ago
3 0

Answer:

B. 48

100-52 = 48

Step-by-step explanation:

When you are finding the range you are taking the lowest and highest numbers and finding the difference. So you would put the numbers in order from least to greatest then find the highest and lowest amounts.  

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Jason is 22 years older than his sister Ann. In 4 years, he will be twice as old as Ann. How old is each of them now?
Ksivusya [100]

Answer:

im not sure if this is rite

Step-by-step explanation:

jason=a+22

ann=a

a+22+4=2a+4

a+26=2a+4

a=22

6 0
3 years ago
I need help. What’s the answer and how do you do this?
erik [133]
Scale factor is 1/2 or 0.5

One of the sides of figure A is 4 units, Same side for Figure B has TWO units.
Which is basically half the size of the original (figure A)
5 0
3 years ago
Plz answer its 5th grade math​
MAVERICK [17]

Answer:

the answer is c I think for that problem

6 0
4 years ago
Please Help me someone! I dont even know where to start.<br> Solve for X
olga55 [171]
We cant answer this because we don't know the equation.
8 0
3 years ago
Laboratory experiment shows that the life of the average butterfly is normally distributed with a mean of 18.8 days and a standa
inessss [21]

Answer:

a) 0.4164

Step-by-step explanation:

Mean lifespan (μ) = 18.8 days

Standard deviation (σ) = 2 days

For any given lifespan 'X', the z-score is:

z=\frac{X- \mu}{\sigma} \\z=\frac{X- 18.8}{2}

For X=12.04 days:

z=\frac{12.04 - 18.8}{2} \\z=-3.38

A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.

For X=18.38 days:

z=\frac{18.38 - 18.8}{2} \\z=-0.21

A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.

The probability that a butterfly lives between 12.04 and 18.38 days is

P=41.68-0.036\\P=41.64\%\ or\ 0.4164

6 0
3 years ago
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