Answer:
<u> BC = 10 and AD = 30</u>
Step-by-step explanation:
In figure-1 , AB = CD ,BK ⊥ AD, AK = 10, KD = 20.
Since, line AD is sum of AK and KD, then
AD = AK + KD
AD = 10 + 20
AD = 30
Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD
so, BC = KL and AK = LD
KL = AD - LD
KL = 20 - 10
KL = 10
Since, BC = KL then BC = 10
Hence, <u> BC = 10 and AD = 30</u>
Rewriting the formula in standard form would be x^2-8x+14=0
The expression coud be re written:
12x²y/2xy + 6xy/2xy + 4x²/2xy . Simplify numerator & denominator whenever it is possible:
6x-3+2x/y
Answer:
answers below
Step-by-step explanation:
1=convergent
2=divergent
3=Transform