What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
2 answers:
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Step-by-step explanation:
y = |x - 2| - 1
Given equation is in the form of y=|x-h|+k
Where (h,k) is the vertex
h = 2 and k =-1
So (2, -1) is the vertex for the given function
To find x intercepts we plug in 0 for y
we will get two values for x because of absolute function
0 = |x-2| -1
add 1 on both sides
|x-2| =1
x-2 =1 and x-2 =-1
x= 3 and x= 1
So x intercepts are (1,0) and (3,0)
the graph is attached below
