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Mama L [17]
3 years ago
14

Three solid shapes A,B and C The surface area of shape A is 9cm² The surface area of shape B is 16cm² The ratio of the volume of

shape B to the volume of shape C is 27 : 125 Work out the ratio of the height of shape A to the height of shape C
Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0

Answer:

9:20

Step-by-step explanation:

Given:

Surface area of shape A = 9 cm²

Surface Area of shape B = 16 cm²

Ratio of volume of shape A to B = 27:125

Required:

Find the ratio of the height of shape A to the height of shape C.

Ratio of surface area (A:B)² = ratio of linear measures (A:B)

Thus,

(A:B)² = (A:B)

(A/B)² = (A/B)

(\frac{A}{B})^2= (\frac{9}{16})

Take the square root of both sides:

(\sqrt{\frac{A}{B}})^2 = (\sqrt{\frac{9}{16}})

\frac{A}{B} = \frac{3}{4}

Ratio of volume of shape B to C = 27:125

Thus,

(B:C)³ = 27:125

(\frac{B}{C})^3= (\frac{27}{125})

Take the cube root of both sides:

(3\sqrt{\frac{B}{C}})^3 = (3\sqrt{\frac{27}{125}})

\frac{B}{C} = \frac{3}{5}

Therefore, ratio of lengths A:B:C =

3:4:C

A:3:5

To make them equivalent, we have:

9:12:C

A:4:20

Therefore, the ratio of the height of shape A to the height of shape C =

9:20

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Based on the information represented by the boxplot ;

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  • Kayla's median is between 200 and 300

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1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

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  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

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  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

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