Please help!!!! graph the function f(x)=-1/5x+4. use the line tool and select two points to graph

Mathematics

2 answers:

-BARSIC- [3]3 years ago

6 0

The beginning is 4 go down 5 and over one

mamaluj [8]3 years ago

3 0

Answer:

(0, 4) and (5, -1)

Step-by-step explanation:

The given function is shown as f(x) = -(1/5)x + 4.

We can re write it as y = -(1/5)x + 4.

In the above equation, putting x = 0 we get y = 4.

Hence the graph passes through (0, 4).

Again in the equation of the line, y = -(1/5)x + 4, putting x = 5 we get y = -1.

Hence the graph passes through (5, -1).

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What is the perimeter of a polygon with vertices at (−2, 1) , (−2, 4) , (2, 7) , (6, 4) , and (6, 1) ?

alekssr [168]

First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
$d = \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }$
$d1 = \sqrt{{(1 - 4)}^{2} + {( - 2 - - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\ = \sqrt{{(3)}^{2} + {( - 4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ {(3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} } \\ = \sqrt{ {(0)}^{2} + {( - 4)}^{2}} = \sqrt{16} \: = 4$
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units

5 0

3 years ago

Read 2 more answers

Answers to 7 and 8 please (:

SpyIntel [72]

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3 years ago

the area of a square vegetable garden is 75 ft squared what is the approximate length of each side of the garden

gizmo_the_mogwai [7]

75ft^2= x^2
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8 0

3 years ago

HELP ME PLEASE!!! this dosent make sense

Andreyy89

Answer:

I think it would be D not sure tho hope this is helpful

4 0