Question

Use the x-intercept method to find all real solutions of the equation. x^3-7x^2+4x+12=0

Answer 1

Answer:

the answer is c for apex

Step-by-step explanation:

Answer 2

Answer:

a. $x=-1,2,\:or\:6$

Step-by-step explanation:

The given equation is

$x^3-7x^2+4x+12=0$

To find all real solutions using the x-intercept method, we to graph the corresponding function using a graphing tool.

The corresponding function is;

$f(x)=x^3-7x^2+4x+12$

The real solutions to $x^3-7x^2+4x+12=0$, are the x-intercepts of the graph of the corresponding function.

From the graph the x-intercepts are

(-1,0),(2,0) and (6,0).

Therefore the real solutions are

$x=-1,2,\:or\:6$