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3 years ago

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A survey asked people of different ages whether they get their news by reading the paper. What is the probability that a person

surveyed is 40 or older and gets the news by reading the paper?

2 answers:

Bingel [31]3 years ago

8 0

C. 60%

The probability that a person surveyed is 40 or older and gets the news by reading the paper is 60%.

Step-by-step explanation:

In our case, we have to find the probability of a person getting their news by reading the paper. But we are given with a condition that the person must be 40 or older.

The survey is conducted among 80 people.

Number of people aged 40 or older = 40

No of people aged 40 or older and read paper = 24

Probability formula is the ratio of number of favorable outcomes to the total number of possible outcomes.

Probability of a person aged 40 or older reads a paper =

(No. of People aged 40 or older and read paper)/(No. of people aged 40 or older)

= 24/40

= 0.6

= 60%

Learn more about probability from brainly.com/question/10694003

#learnwithBrainly

Darina [25.2K]3 years ago

3 0

Answer:

60%

Step-by-step explanation:

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Account A and Account B both have a principal of $2,000 and an annual interest rate of 2%. No additional deposits or withdrawals

GuDViN [60]

Answer:

Account B earns more interest.

After 20 years, account B will have earned $171.89 more.

Step-by-step explanation:

Let's calculate the total for each account.

Account A:

Account A earns simple interest. We know that the principal value is $2000 and the interest rate is 2% or 0.02. We can use the simple interest formula:

$A=P(1+rt)$

Where A is the future value, P is the principal, r is the rate, and t is the time in years.

So, let's substitute 2000 for P, 0.02 for r, and 20 for t. This yields:

$A=2000(1+0.02(20))$

Multiply and add:

$A=2000(1+0.4)=2000(1.4)$

Multiply. So, the total amount of money in Account A after 20 years is:

$A=\$2800$

Since we initially deposited $2000 and our total is now $2800, this means that we earned an interest of $2800-2000=\$ 800$

Account B:

Account B earns compound interest. Like Account A, Account B has a principal value of $2000 and the interest rate is 2% or 0.02. We also know that it's compounded annually, so once per year. We can use the compound interest formula:

$B=P(1+\frac{r}{n}})^{nt}$

Where B is the future value, P is the principal, r is the rate, n is the times compounded per year, and t is the time in years.

So, let's substitute 2000 for P, 0.02 for r, n for 1 (since it's compounded annually), and t for 20. This yields:

$B=2000(1+\frac{0.02}{1})^{(1)(20)}$

Simplify this to acquire:

$B=2000(1.02)^{20}$

Evaluate. Use a calculator. So, after 20 years, the amount of money in Account B is:

$B\approx\$2971.89$

Since our principal was $2000, this means that we earned an interest of approximately $2971.89-2000=\$ 971.89$ .

So, Account A earned an interest of $800 and Account B earned an approximate interest of $971.89.

So, Account B earned more interest.

And it earned $971.89-800=\$ 171.89$ more than Account A.

And we're done!

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melisa1 [442]

Answer:

x=-48

Step-by-step explanation:

Add 4 to both sides and then multiply both sides by 3.

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What is the side length of the square if A=81 m squared

Nesterboy [21]

Answer:

The side length is 9m

Step-by-step explanation:

A = 81 m^2

Since the figure is a square, we know the area of a square is A = s^2 where s is the side length

81 m^2 = s^2

Take the square root of each side

sqrt(81 m^2 ) = sqrt( s^2)

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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

so

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

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3 years ago