Answer :36in2
example:
my math teacher told me
Answer:
( $74.623, $83.777)
The 90% confidence interval is = ( $74.623, $83.777)
Critical value at 90% confidence = 1.645
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = $79.20
Standard deviation r = $10.41
Number of samples n = 14
Confidence interval = 90%
Using the z table;
The critical value that should be used in constructing the confidence interval.
z(α=0.05) = 1.645
Critical value at 90% confidence z = 1.645
Substituting the values we have;
$79.20+/-1.645($10.42/√14)
$79.20+/-1.645($2.782189528308)
$79.20+/-$4.576701774067
$79.20+/-$4.577
( $74.623, $83.777)
The 90% confidence interval is = ( $74.623, $83.777)
Answer:
x f(x) g(x)
1 15 3
2 16 4
3 15 5
4 12 6
5 7 7
6 0 8
f(x) = g(x) when x = 5
Step-by-step explanation:
f(x) = -x² + 4x + 12
f(1) = -(1)² + 4(1) + 12 = 15
f(2) = -(2)² + 4(2) + 12 = 16
f(3) = -(3)² + 4(3) + 12 = 15
f(4) = -(4)² + 4(4) + 12 = 12
f(5) = -(5)² + 4(5) + 12 = 7
f(6) = -(6)² + 4(6) + 12 = 0
g(x) = x + 2
g(1) = 1 + 2 = 3
g(2) = 2 + 2 = 4
g(3) = 3 + 2 = 5
g(4) = 4 + 2 = 6
g(5) = 5 + 2 = 7
g(6) = 6 + 2 = 8
This isn't a question. What is the question?