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castortr0y [4]
4 years ago
15

When the cost of a car is multiplied by 0.02 the result is $1730. Find the cost of the car

Mathematics
2 answers:
Harman [31]4 years ago
8 0
Remember you can do anything to an equation as long as you do it to both sides

cost times 0.02=1730
divide both sides by 0.02
cost=1730/0.03
cost=86500 or 86500.00


the cost is $86500

jeka57 [31]4 years ago
8 0
Let, the cost of Car = x

Then, x * 0.02 = 1730

Now, You can write 0.02 as 2/100   [ By excluding the decimal from expression ]

So, x * 2/100 = 1730

x = 1730 * 100 / 2

x = 1730 * 50

x = 86500

In short, Price of the Car would be: $86500

Hope this helps!
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\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
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