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elena-14-01-66 [18.8K]
3 years ago
7

Solye for x. 8(x + 1) - 3[X + 4) = 7(2 - x)

Mathematics
1 answer:
kramer3 years ago
4 0

Answer:

3/2

Step-by-step explanation:

distribute 8,-3,7

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Madaraka express arrived in Mombasa at 0545hrson Thursday after travelling for
Liono4ka [1.6K]

Answer:

Step-by-step explanation:

For this question, you count backwards from 0545hrs which is 5:45 am until 7hrs is reached.

5:45 am Thursday

↓

4:45 am Thursday

↓

3:45 am Thursday

↓

2:45 am Thursday

↓

1:45 am Thursday

↓

12:45 am Thursday

↓

11:45pm Wednesday

↓

10:45 pm Wednesday

Therefore, Madaraka express left Nairobi at 10:45 pm on Wednesday

4 0
3 years ago
Help me find Sample variance and standard deviation
AnnZ [28]
First, find the mean. You'll need it to compute the variance.

\bar x=\displaystyle\frac15\sum_{i=1}^5x_i=\dfrac{21+10+6+7+11}5=11

The variance of the sample is then computed with the formula

s^2=\displaystyle\dfrac1{5-1}\sum_{i=1}^5(\bar x-x_i)^2=\dfrac{(21-11)^2+\cdots+(11-11)^2}4=\dfrac{71}2=35.5

The standard deviation is the square root of the variance, so

s=\sqrt{35.5}\approx5.958
5 0
3 years ago
The slope of the line below is 3. Use the coordinates of the labeled point (6, 8) to find a point-slope equation of the line.
Marina CMI [18]
<span>point-slope equation

y - 8 = 3(x - 6)

hope it helps</span>
5 0
3 years ago
Read 2 more answers
A triangle has sides of (2x), (x - 7) and (3x - 20).
LiRa [457]
2x+x-7+3x-20=87cm
6x-27=87
6x=114
x=19
Therefore the sides are:12cm, 38cm, and 37cm
7 0
3 years ago
Write the slope-intercept form of the equation of the line described.
Ad libitum [116K]

                                                  7)

Given the line

y=-x+2

We know that the slope-intercept form of the line equation is

y=mx+b

here

m is the slope and b is the intercept

Thus, the slope = -1

We know that the parallel lines have the same. Thus, the slope of the parallel line is: -1

Using point-slope of the line equation

y-y_1=m\left(x-x_1\right)

substituting the values m = -1 and the point (4, 0)

y-0 = -1 (x-4)

Writing in the slope-intercept form

y = -x+4

Thus, the slope-intercept form of the equation of the line equation parallel to y=-x+ 2 will be:

  • y = -x+4

                                                      8)

<em>Note: </em><em>Your line is a little bit unclear. But, I am assuming the</em>

<em>ine is: </em>y = -x-1

<em />

Given the assumed line

y = -x-1

We know that the slope-intercept form of the line equation is

y=mx+b

here

m is the slope and b is the intercept

Thus, the slope = m = -1

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = -1

perpendicular slope = – 1/m = -1/-1 = 1

Using point-slope of the line equation

y-y_1=m\left(x-x_1\right)

substituting the values m = 1 and the point (4, 3)

y - 3 = 1 (x-4)

Writing in the slope-intercept form

y-3 = x-4

y = x-4+3

y = x - 1

Thus, the slope-intercept form of the equation of the line equation perpendicular to y = -x-1 will be:

  • y = x - 1

5 0
3 years ago
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