If you would like to know in which step did the student first make an error and what is the correct step, you can calculate this using the following steps:
3(2x - 4) = 8 + 2x + 6
6x - 12 = 8 + 2x + 6
6x - 12 = 14 + 2x ... Step 2
6x - 2x = 14 + 12
4x = 26
x = 26/4 = 13/2
The correct result would be Step 2; <span>6x - 12 = 14 + 2x.</span>
Answer:
because would die of boredom .and i wouldn't have Netflix or Hulu.and i would have nothing to look forward. to when i come home from school i would have to just go and do homework. and without TV you would not have a news channel so you wouldn't know things to are important to life.
Step-by-step explanation:
Answer: The number is 26.
Step-by-step explanation:
We know that:
The nth term of a sequence is 3n²-1
The nth term of a different sequence is 30–n²
We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.
we get:
3n²- 1 = 30–m²
Notice that as n increases, the terms of the first sequence also increase.
And as n increases, the terms of the second sequence decrease.
One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.
if m = 1, then:
3n²- 1 = 30–1²
3n²- 1 = 29
3n² = 30
n² = 30/3 = 10
n² = 10
There is no integer n such that n² = 10
now let's try with m = 2, then:
3n²- 1 = 30–2² = 30 - 4
3n²- 1 = 26
3n² = 26 + 1 = 27
n² = 27/3 = 9
n² = 9
n = √9 = 3
So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.
the number is:
3*(3)² - 1 = 26
30 - 2² = 26
The number that belongs to both sequences is 26.
