Step-by-step explanation:
know the normal large sample condition is not met and also there are outliers
Answer:
ohhh yea that's a umm carot
I would distribute first.
Hope this helps.
頑張って!
Answer:
0.1105
Step-by-step explanation:
We know that question about reporting a cheating is asked to 172 students.
So the sample size would be n=172.
Out of 172 undergraduate students only 19 students answered "yes". It means that only 19 out of 172 students are willing to report cheating and so x=19.
According to definition of proportion
proportion=number of favorable outcome/total number of outcome
p=x/n
we are given that x=19 and n=172 so,
p=19/172=0.1105.
Hence according to given data 11.05% of students are wiling to report cheating by other students.
I’m thinking the answer would be D
