How many times wider is 2ft than the width of 2in
2 answers:
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Answer:
4 games played = 1/56
5 games played = 5/56
6 games played = 15/56
7 games played = 35/56
Step-by-step explanation:
The probability of each time winning is 0.5
So there are a couple of ways the series could go.
- Team A could win all first 4 matches. We can depict this as A-A-A-A
- Team A could win 4, while having lost 1. Lets depict this a A-B-A-A-A
- Team A could win 4, while having lost 2. A-B-B-A-A-A
- Team A could win 4, while having lost 3. A-B-B-B-A-A-A
These 4 possibilities could be repeated with B winning as well. It should be noted that these are the only ways for the series to end. We find the number of permutations of each possibility above to find their probability.
I advise you to study 'how to permute identical objects' for this.
These permutations are stated below:
1. 4!/4! = 1
2. = 5
3 = 15
4 = 35
These are they ways A or B could win. The total is 1+5+15+35 = 56. The answer given thus reflects the possibilities.
Answer:
Step-by-step explanation:
Understanding the problem:
x -----> number of munchkins
y -----> number of yema
Devise a plan:
x + y ≥ 10
3x + 2y ≥ 50
Carry out:
y ≥ -x + 10 ------------(I)
3x + 2y ≥ 50
2y ≥ -3x + 50
y ≥