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svetlana [45]
3 years ago
14

Help me please!!!!!!!

Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0
The answer would be B
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Two classes are planning to go on a field trip together. One clas with 18 students is being joined by 6 boys and 11 girls from a
Serjik [45]

Answer: The boys made up 6b of the original class.

Step-by-step explanation:

7 0
3 years ago
A group of friends wants to go to the amusement park. they have no more than $405 to spend on parking and admission. parking is
lakkis [162]

20+38.50x \leq 405

4 0
1 year ago
What are the characteristics of the graph of the inequality x ≥ -2? The ray will move to the left. The ray will move to the righ
Alenkasestr [34]

Answer:

Step-by-step explanation:

The inequality x ≥ -2 is graphed on a number line.  -2 is the smallest possible value.  All subsequent values are larger and therefore lie to the right of -2.

Thus, the following are true:

1.  The ray will move to the right (because x begins at -2 and increases, which means moving to the right on the number line).

2.  It will use a closed circle (because x = -2 is part of the solution set).

6 0
3 years ago
Which of the following options have the same value as 10\%10%10, percent of 333333?
Contact [7]

Answer:

The answer is C, D, and E

Step-by-step explanation:

6 0
3 years ago
Keisha's boat has a top speed of 9 miles per hour in still water. While traveling on a river at top speed, she went 10 miles ups
neonofarm [45]
If she went 10 miles upstream in the same time as she went 20 miles downstream, that means the downstream speed is twice the upstream speed.

The speed is still water is 9 mph.
The speed of the current is c.
Going downstream, the current adds speed, so the sped downstream is 9 + c.
The speed upstream is 9 - c.
9 + c is twice 9 - c.

9 + c = 2(9 - c)

9 + c = 18 - 2c

3c = 9

c = 3

Answer: The speed of the current is 3 mph.

Check:
9 + c = 12
9 - c = 6
By taking into the account the speed of the current, the downstream speed, 12 mph, is indeed twice the upstream sped, 6 mph.

6 0
3 years ago
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