What steps Do you need To take to solve the equation 1/2×+6=18?

Mathematics

2 answers:

DIA [1.3K]4 years ago

6 0

Well I think it's D. You subtract 6 from both sides, then you multiply by 2 on both sides to get rid of the fraction:

1/2x + 6 = 18

1/2x = 18-6

1/2x = 12

1/2x * 2 = 12 * 2

x = 24

JulijaS [17]4 years ago

3 0

First -6 on both sides then divide 1/2 (which would be times 2) and then answer would be 24
Hope this helps :)

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If cos(θ)= -2/3 and θ lies in quadrant II, find the value of cotθ

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$\text{Given that,}\\\\\cos \theta = - \dfrac 23\\\\\implies \cos^2 \theta = \dfrac 49\\\\\implies 1- \sin^2 \theta = \dfrac 49\\\\\implies \sin^2 \theta =1-\dfrac 49\\\\\implies \sin^2 \theta =\dfrac 59\\\\\\\text{Now,}\\\\\cot^2 \theta = \dfrac{\cos^2 \theta}{\sin^2 \theta} \\\\\\\implies \cot^2 \theta = \dfrac{\tfrac 49}{\tfrac 59}\\\\\\\implies \cot^2 \theta = \dfrac 49 \times \dfrac 95\\\\\\\implies \cot^2 \theta = \dfrac 45\\\\\\$

$\implies \cot \theta = \pm\sqrt{\dfrac 45} = \pm \dfrac 2{\sqrt 5}\\\\\\\text{Since}~ \theta ~ \text{lies in the second quadrant,} \cot \theta ~\text{will be negative.}\\\\\text{Hence,}~ \cot \theta = - \dfrac{2}{\sqrt 5}$