Answer:
m<NQS = 32°
Step-by-step explanation:
Given:
m<BQS = 80°
m<BQN = 48°
Required:
m<NQS
SOLUTION:
Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.
Therefore:
m<BQN + m<NQS = m<BQS (angle addition postulate)
48° + m<NQS = 80° (substitution)
m<NQS = 80 - 48° (Subtraction of 48 from each side)
m<NQS = 32°
Answer:
After the reflection over the line y = -x, the image of the point is: (-3,-2)
Step-by-step explanation:
When a given point is reflected over a line the point only changes place but the distance between the point and the line remains same.
Let (x,y) be a point on the plane
and
y = -x be a line on the plane
When a point is reflected over a line y = -x , the coordinates of the point are exchanged which means x becomes y and y becomes x and both are negated
So (x,y) will become (-y,-x)
Given point is:
(2,3)
After the reflection over the line y = -x, the image of the point is: (-3,-2)
ANSWER
B. 10
EXPLANATION
We need to find the value of x first.
It was given that the perimeter of triangle XYZ is 24.
This means that:
XY+YZ+XZ=24
we substitute the expression in terms of x to get;
This implies that
Divide both sides by 4 to get;
|WY|=|ZX|=13-3=10
Answer:
No solution
Step-by-step explanation:
The question is 4(3x-5)=12x-24
so we do the step:12x-20=12x-24
No solution.
