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densk [106]
1 year ago
12

PLEASE HELP, TIMED

Mathematics
1 answer:
kogti [31]1 year ago
4 0

The Chebyshev Theorem guarantees that we will find at least 75% of the people with wages between $9.25 and $14.25.

<h3>What does Chebyshev’s Theorem state?</h3>

When the distribution is not normal, Chebyshev's Theorem is used. It states that:

  • At least 75% of the measures are within 2 standard deviations of the mean.
  • At least 89% of the measures are within 3 standard deviations of the mean.
  • An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

The Chebyshev Theorem guarantees that we will find at least 75% of the people with wages within 2 standard deviations of the mean, hence the bounds are:

  • 11.75 - 2 x 1.25 = $9.25.
  • 11.75 + 2 x 1.25 = $14.25.

More can be learned about the Chebyshev Theorem at brainly.com/question/25303620

#SPJ1

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A United Nations report shows the mean family income for Mexican migrants to the United States is $27,000 per year. A FLOC (Farm
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We conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

Step-by-step explanation:

We are given that a United Nations report shows the mean family income for Mexican migrants to the United States is $27,000 per year.

A FLOC  evaluation of 25 Mexican family units reveals a mean to be $30,000 with a sample standard deviation of $10,000.

Let \mu = <em><u>true mean family income for Mexican migrants.</u></em>

So, Null Hypothesis, H_0 : \mu = $27,000     {means that the mean family income for Mexican migrants to the United States is $27,000 per year}

Alternate Hypothesis, H_A : \mu \neq $27,000     {means that the mean family income for Mexican migrants to the United States is different from $27,000 per year}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                          T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean family income = $30,000

            s = sample standard deviation = $10,000

            n = sample of Mexican family = 25

So, <u><em>the test statistics</em></u>  =  \frac{30,000-27,000}{\frac{10,000}{\sqrt{25} } }  ~ t_2_4

                                     =  1.50

The value of t test statistics is 1.50.

Since, in the question we are not given the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -2.064 and 2.064 at 24 degree of freedom for two-tailed test.</u>

Since our test statistic lies within the range of critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean family income for Mexican migrants to the United States is $27,000 per year and the provided information is consistent with the United Nations report.

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3 years ago
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