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densk [106]
1 year ago
12

PLEASE HELP, TIMED

Mathematics
1 answer:
kogti [31]1 year ago
4 0

The Chebyshev Theorem guarantees that we will find at least 75% of the people with wages between $9.25 and $14.25.

<h3>What does Chebyshev’s Theorem state?</h3>

When the distribution is not normal, Chebyshev's Theorem is used. It states that:

  • At least 75% of the measures are within 2 standard deviations of the mean.
  • At least 89% of the measures are within 3 standard deviations of the mean.
  • An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

The Chebyshev Theorem guarantees that we will find at least 75% of the people with wages within 2 standard deviations of the mean, hence the bounds are:

  • 11.75 - 2 x 1.25 = $9.25.
  • 11.75 + 2 x 1.25 = $14.25.

More can be learned about the Chebyshev Theorem at brainly.com/question/25303620

#SPJ1

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Sarah deposits $600 in a savings account that pays 2.5% per year. What is the minimum number of years it would take for the amou
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Here is the compound interest formula solved for years:
<span>Years = {log(total) -log(Principal)} ÷ log(1 + rate)
</span>Years = {log(800) - log(600)} <span>÷ log(1.025)
</span><span>Years = {2.903089987 -2.7781512504} / 0.010723865392
</span>Years = { <span> <span> <span> 0.1249387366 } / </span></span></span><span><span><span>0.010723865392
</span> </span> </span> Years = <span> <span> <span> 11.6505319708 </span> </span> </span>
That's how many years it takes for the $600 to become exactly $800.00
The question specifically asks how long for the money to be MORE than $800.00?

So, if we enter 800.01 into the equation, then the answer is
Years = {log(800.01) - log(600)} <span>÷ log(1.025)
</span><span>Years = {2.9030954156 -2.7781512504} / 0.010723865392
</span>Years = <span> <span> <span> 0.1249441652 </span> </span> </span> / 0.010723865392
<span> <span> <span> Years = 11.6510381875 </span> </span> </span>
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Step-by-step explanation:

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A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa
yarga [219]

Answer:

z= \frac{85-70}{10}=1.5

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

E(X)= \mu =70, SD_X=\sigma=10  

The z score is given by:

z=\frac{x-\mu}{\sigma}

If we use this we got:

z= \frac{85-70}{10}=1.5

Let Y the random variable that represent the scores for his friend, and for this case we know that:

E(Y)= \mu =35, SD_Y=\sigma=5  

The z score is given by:

z=\frac{y-\mu}{\sigma}

If we use this we got:

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

3 0
3 years ago
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