I used an online calculator
and got this when i simplified-
-1/2(2x-3)
Answer:
34175 people will live in Pattersonville 8 years from now
Step-by-step explanation:
Initial population of Pattersonville =40,500
We are given that The census indicated that the population of the town has been decreasing by 2.1% per year .
Now we are supposed to find If this trend continues , approximately how many people will live in Pattersonville 8 years from now
Formula : 
Where N(t)= Population after t years
= Initial population
r = rate of decrease = 2.1 %=0.021
t = 8 years
Substitute the values in the formula :
So,
N(8)=34175.63223
So, 34175 people will live in Pattersonville 8 years from now
Answer:
-4 in
Step-by-step explanation:
4 inches underground, assuming that ground level is 0, is negative four inches.
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Answer:
2
Step-by-step explanation:
-2y+10+2y-8
-2y+2y+10-8
10-8
2