3 years ago

Log(3)+log(5) in to log (c)

Mathematics

1 answer:

sineoko [7]3 years ago

6 0

Step-by-step explanation:

$log \: (3) + log \: (5) \\ = log \: (3 \times 5) \\ = log \: (15) \\$

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let's convert the mixed fractions to improper fractions firstly.

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$\bf \cfrac{19}{8}-\cfrac{9}{2}+\cfrac{25}{8}-\cfrac{1}{2}\implies \stackrel{\textit{using an LCD of 8}}{\cfrac{(1)19-(4)9+(1)25-(4)1}{8}}\implies \cfrac{19-36+25-4}{8} \\\\\\ \cfrac{4}{8}\implies \cfrac{1}{2}$

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when you plug them in it should look like this

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