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boyakko [2]
4 years ago
14

Strontium 90 is a radioactive material that decays according to the function Upper A (t )equals Upper A 0 e Superscript negative

0.0244 t Baseline commaA(t)=A0e−0.0244t, where Upper A 0A0 is the initial amount present and A is the amount present at time t​ (in years). Assume that a scientist has a sample of 500500 grams of strontium 90. ​(a) What is the decay rate of strontium​ 90?
Mathematics
1 answer:
zvonat [6]4 years ago
7 0

Answer:

Decay rate K = -2.44%

Step-by-step explanation:

From the question, we want to know the decay rate of strontium 90

Mathematically, this is accessible from its decay equation

From the decay equation, we can see that that ;

At = Ao e^-0.0244t

Generally, the decay equation of a radioactive sample can be written as

At = Ao e^-kt

where K represents the decay constant

From the equation, we can see that;

k = 0.0244 which when represented as a percentage is 2.44%

Since it’s a decay we can say that the decay rate is -2.44%

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Step-by-step explanation:

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Use this graph of velocity vs. time for two objects to answer the question.
Lynna [10]

Using derivatives, it is found that the correct option is:

A. Object C has an acceleration that is greater than the acceleration for D.

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a = \frac{\Delta_v}{\Delta_t}

In this problem:

  • The change in time for objects C and T is the same.
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Complete the square to transform the expression x2 + 4x + 2 into the form a(x − h)2 + k.
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Answer:

Step-by-step explanation:

y = (x^2 + 4x)      + 2

Take 1/2 of the linear term 4/2 = 2 and square that result. 2^2 = 4.

Put it after 4x

y = (x^2 + 4x + 4)   +2  Subtract what you put inside the brackets on the outside.

y = (x^2 + 4x + 4) + 2 - 4      Combine the right.

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3 0
3 years ago
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lapo4ka [179]

Answer: The correct options are  (1) (5,10), (2) (3,-3), (3) x = -1, (4) y=(x+2)^2+3, (5) 21s and (6) 0, -1, and 5.

Explanation:

Te standard form of the parabola is,

f(x)=a(x-h)^2+k        .....(1)

Where,  (h,k) is the vertex of the parabola.

(1)

The given equation is,

f(x)=(x-5)^2+10

Comparing this equation with equation (1),we get,

h=5 and k=10

Therefore, the vertex of the graph is (5,10) and the fourth option is correct.

(2)

The given equation is,

f(x)=3x^2-18x+24

f(x)=3(x^2-6x)+24

To make perfect square add (\frac{b}{2a})^2, i.e., 9. Since there is factor 3 outside the parentheses, so subtract three times of 9.

f(x)=3(x^2-6x+9)+24-3\times 9

f(x)=3(x-3)^2-3

Comparing this equation with equation (1),we get,

h=3 and k=-3

Therefore, the vertex of the graph is (3,-3) and the fourth option is correct.

(3)

The given equation is

f(x)=4x^2+8x+7

f(x)=4(x^2+2x)+7

To make perfect square add (\frac{b}{2a})^2, i.e., 1. Since there is factor 4 outside the parentheses, so subtract three times of 1.

f(x)=4(x^2+2x+1)+7-4

f(x)=4(x+1)^2+3

Comparing this equation with equation (1),we get,

h=-1 and k=3

The vertex of the equation is (-1,3) so the axis is x=-1 and the correct option is 2.

(4)

The given equation is,

y=x^2+4x+7

To make perfect square add (\frac{b}{2a})^2, i.e., 2^2.

f(x)=x^2+4x+4+7-4

f(x)=x^2+4x+4+7-4

f(x)=(x+2)^2+3

Therefore, the correct option is  4.

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h=-16t^2+672t

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x=\frac{b}{2a}

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Therefore,  after 21 seconds the projectile reach its maximum height and the correct option is first.

(6)

The given equation is,

f(x)=3x^3-12x^2-15x

f(x)=3x(x^2-4x-5)

Use factoring method to find the factors of the equation.

f(x)=3x(x^2-5x+x-5)

f(x)=3x(x(x-5)+1(x-5))

f(x)=3x(x-5)(x+1)

Equate each factor equal to 0.

x=0,-1,5

Therefore, the zeros of the given equation is 0, -1, 5 and the correct option is 2.

3 0
3 years ago
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