Question

In a parallel circuit et= 240 v ,r = 30 ohms and xl = 40 ohms what is the power factor

Answer 1

Answer:

$PF=2400$ kVA units.

Step-by-step explanation:

Given : In a parallel circuit et= 240 v ,r = 30 ohms and xl = 40 ohms.

To find : What is the power factor?

Solution :

In a parallel rl circuit we have,

Total voltage, et= 240 Volts,

Resistance, r= 30 ohm,

Inductive Reactance, xl= 40 ohm.

In parallel circuit, the voltage across resistor and inductor remains same.

i.e. vr = vl= v= 240 Volts

Using Ohm's Law,

The current across resistor would be $ir=\frac{v}{r}$

$ir=\frac{240}{30}$

$ir=8\ amp$

Using Ohm's Law,

The current across inductor would be $il=\frac{v}{xl}$

$il=\frac{240}{40}$

$il=6\ amp$

Now, Total current would be $(it)^2= (ir)^2+ (il)^2$

$(it)^2= (8)^2+ (6)^2$

$(it)^2= 64+36$

$(it)^2= 100$

$it= 10$

The voltage is 240 V and current is A= 10 amp

The power factor is $PF=V\times A$

$PF=240\times 10$

$PF=2400$ kVA units.