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cricket20 [7]
3 years ago
12

I need help wit this

Mathematics
1 answer:
balu736 [363]3 years ago
5 0
I hope this helps you

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Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview
mario62 [17]

Answer:  The required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

Step-by-step explanation:   We are given to solve the following differential equation :

5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.

So, the general solution of the given equation is

y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.

Differentiating with respect to t, we get

y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.

According to the given conditions, we have

y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

and

y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.

From equation (ii), we get

B=\dfrac{7}{3}.

Thus, the required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

7 0
3 years ago
Which phrase best describes the transformation from the graph of y=(2x-15)^2+3 to the graph of y=2(x-11)^2+3?
weeeeeb [17]

Answer:

The graph's vertex would move 4 to the right and would become twice as wide.

Step-by-step explanation:

We can tell this because the x value of the vertex is the constant inside the parenthesis. In this case, the number changes from 11 to 15, which means it moves to the right by 4.

And with the 2 outside of the parenthesis instead of inside, it becomes more wide (since the 2 is not being squared).

7 0
3 years ago
(X+8)(x-8) if necessary combine like terms
julia-pushkina [17]

Answer:

x² - 64

Step-by-step explanation:

Given

(x + 8)(x - 8)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x - 8) + 8(x - 8) ← distribute both parenthesis

= x² - 8x + 8x - 64 ← collect like terms

= x² - 64

3 0
3 years ago
Can u guys please help me
blsea [12.9K]

Answer:

60.69cm^2

Step-by-step explanation:

5.1^2 = 26.01

5.1/2 = 2.55

2.55 × 5.95 = 15.1725

15.1725×4 = 60.69

60.69 + 26.01 = 60.69cm^2 nice

4 0
2 years ago
Which expression represents the distance between 1.8 and 9.4 on the number line?
zhuklara [117]

Answer:

|9.4-1.8|

Step-by-step explanation:

To find distance, you take the largest value minus the smallest value and then take the absolute value of that because distance can't be negative.

7 0
3 years ago
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