Question

Find -3a2 - b3 + 3c2 - 2b3 if a = 2, b = -1, and c = 3

Answer 1

If a = 2, b = -1 and c = 3
-3a^2 - b^3 + 3c^2 - 2b^3 = -3(2)^2 - (-1)^3 + 3(3)^2 - 2(-1)^3 = -3(4) - (-1) + 3(9) - 2(-1) = -12 + 1 + 27 + 2 = 18