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OLEGan [10]
3 years ago
12

Which graph represents the function?

Mathematics
2 answers:
IRISSAK [1]3 years ago
8 0
Of course, I would just graph it on Desmos.com or my graphing calculator and be done.

f(x) can be factored as
.. f(x) = (x -6)(x +1)/((x -3)(x +2))

so will have zeros at x = {-1, 6}, vertical asymptotes at x = {-2, 3}, and sign changes at all of those points.

The Upper Right graph is the only one with the zeros and asymptotes in the right places.

scZoUnD [109]3 years ago
5 0
The bottom factors to (x - 30(x + 2) so there are asymptotes  at x = -2 and x = 3. Also y intercept id  at (0,1) so its either graph 2 or graph 4.
Between x = 0 and x = 3   y  is increasing so the correct graph is Graph 2.
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blsea [12.9K]

(For question 1 you have to do it yourself, get a ruler and measure the actual length of the drawing, then multiply it by 8 to get the actual dimensions in the exercise. )

Example, if you measure 4 inches, the actual dimension will be 4 x 8 = 32 ft

2. (Scale drawing 1:5 is that every 1 (length units) will be equal to 5(length units) in the actual dimensions)

Model : 3ft ; 7m
Actual : 15ft ; 35m (corresponding)

Actual : 20yd ; 12.5 cm
Model : 4yd ; 2.5 cm

6. 1.5 ft = 1.5 x 12 = 18 inches.
The model is 3 inches, and the actual rose is 18 inches -> The scale of the drawing is 6. (enlargement)

Same goes to the scale factor, but this time is the quotient of the corresponding side -> 3 : 18 = 1:6.

(If I got any parts wrong just tell me, I actually kinda forgot these kind of stuff)


8 0
2 years ago
Ms. Manko has 4 grams of sprinkles
lukranit [14]
4 divided by 12 is 1/3.
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6 0
2 years ago
What is 4/3 subtracted by 2/5
yKpoI14uk [10]

In order to subtract fractions, we must find a common denominator, then subtract the numerators.

The common denominator (LCM(3, 5)) is 15.

We must multiply the first numerator by 5, because 3*5=15 and the second numerator by 3 because 5*3=15.

We get \frac{20}{15} - \frac{6}{15}.

All we need to do now is subtract the numerators: \frac{14}{15}.

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7 0
3 years ago
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For the function f(x)=(1/2)⋅6^x , identify the domain, range, y-intercept, and asymptote.
skelet666 [1.2K]

Answer:

Step-by-step explanation:

f(x) = (1/2) *6^x = 2^-1 * 2^x *3^x

y= 2^ (x-1) * 3^x

Domain represents all values that x can have and is all real numbers

Range all values that y can have and is y > 0 ( all real numbers that are positive)

The y-intercept is the point where the graph intersects the y-axis so x=0 there

y = 2^(0-1) *3^0 = 1/2 *1 = 1/2

the asymptote is at y= 0

6 0
3 years ago
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