The blood cells that are necessary for the clotting of blood are

Harman [31]

The correct answer among all of the given choices would be the third choice, CLOUDS.

I hope this is the answer you were looking for and that it helps!! :)

3 0

3 years ago

Which of the following reasons explains why it is important for new scientific findings to be published?

kumpel [21]

Answer:

D - Other scientists can validate or disprove the findings

Explanation:

Publishing findings of their research projects is important as it enables peer-revision on their journals. The work can then be evaluated by the community at-large to validate or disprove it, which opens the dialogue with associate researchers.

4 0

2 years ago

Researchers investigating the regulation of neurotransmitter release from presynaptic neurons proposed a model in which CDK5, a

GrogVix [38]

Answer:

"GFP contained in synaptic vesicles moved into the synaptic cleft by exocytosis."

Explanation:

Synaptic vesicles are small membrane sacs that carry neurotransmitters from the cell body where they are produced, to the presynaptic membrane of the terminal button where they are released. The release zone of the presynaptic membrane contains voltage-dependent calcium channels. When an action potential depolarizes the presynaptic plasma membrane, $Ca^{2+}$ -channels open, and $Ca^{2+}$ flows into the nerve terminal to trigger the exocytosis of synaptic vesicles, thereby releasing their neurotransmitters into the synaptic cleft

3 0

2 years ago

What effect on the body does a lack of insulin have?

ludmilkaskok [199]

Insulin is such a vital secretion of the pancreas in the human body that without it, our body would not function normally. It is responsible for breaking down the food we eat and converting it to energy and then storing that energy. Lack of insulin means that the pancreas are not producing insulin which leads to diabetes. That means that there is a concentration of glucose in the blood rather than being distributed to cells to carry out functions. This can lead to kidney failures, nerve damaging stomach problems and problems in the eyes.

7 0

3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago