y=−1/3x+1

x = -6, y = −1/3(-6) +1 = 3
x = -3, y = −1/3(-3) +1 = 2
x = 0, y = 1
x = 3, y = −1/3(3) +1 = 0
x = 6, y = −1/3(6) +1 = -1

Table
x y
-6 3
-3 2
0 1
3 0
6 -1

8 0

3 years ago

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Write the following ratio using two other notations. 7 to 6

trasher [3.6K]

7:6 and 7/6. hope this helps.

3 0

3 years ago

Find the missing lengths: LO=5 and OK=4, find OH and KH.

hodyreva [135]

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of OH and KH.

In ΔLOH

By Pythagoras theorem

$LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2$ → (1)

In ΔKOH,

$KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2$ → (2)

In ΔKHL,

$KL^2=LH^2+KH^2$

Using eq (1) and (2), we get

$KL^2=5^2+OH^2+OH^2+4^2$

$9^2=25+2OH^2+16$

⇒ $2OH^2=81-25-16=40$

⇒ $OH=\sqrt{20}=6.324\sim6.3units.$

Put the above value in eq 2, we get

$KH^2=20+4^2=36$

⇒ KH=6 units.

8 0

3 years ago

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Please help my dudes

Illusion [34]

Angle-angle-side congruence

3 0

3 years ago