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Marianna [84]
2 years ago
7

The defense of a professional football team scored about 24% of the 242 points the team scored all season. If a touchdown is wor

th 6 points, which could be the number of touchdowns scored by the defense?
Mathematics
2 answers:
irina [24]2 years ago
8 0
So baby you don’t worry you are my only you’ll be lonely even if the sky is falling doooowwwwwnnnn even if the sky is falling down
QveST [7]2 years ago
7 0

Answer:

the answer is 9.69 or if no decimals 10

Step-by-step explanation:

24% of 242 is 58.08 you then divide that number with 6/ the amount of points they get every touchdown. you divide those numbers and you get 9.69.

and that's the amount of points they got but if there aren't any decimals in this question then it would be closer to 100 than it would be 0 so the answer is 10 points

i hope this helped. :)

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Please help me i need an answer
kow [346]
Julie wants to buy cartons of apple juice with $55. Each carton costs $3.75.
Let x be the number of cartons she can buy.

3.75x =< 55
Divide both sides by 3.75
3.75x / 3.75 =< 55/3.75
x =< 14.66666

Of course, she can't buy 14.666 cartons so we can the integer part only. Julie can buy 14 cartons of Juice.

Hope this helps! :D
8 0
3 years ago
James bought a bag of 12 dinner rolls he used 1/6 of the bag how many dinner rolls did james use?
Ierofanga [76]

Answer:

2 is the answer

Step-by-step explanation:

12 divided by 1 divided by 6 = 2

hope this helps plz mark as brainliest

4 0
3 years ago
Solving for matrices
muminat

Answer:

D

Step-by-step explanation:

The augmented matrix for the system of three equaitons is

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\5&2&-2&|&11\\5&-4&4&|&-7\end{array}\right)

Multiply the first row by 5, the second row by -3 and add these two rows:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)

Subtract the third row from the second:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)

Divide the third row by 6:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)

Now multiply  the third equation by 26 and add it to the second row:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)

You get the system of three equations:

\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.

From the third equation

z=\dfrac{90}{45}=2.

Substitute z=2 into the second equation:

-26y-19\cdot 2=-168\\ \\-26y-38=-168\\ \\-26y=-168+38=-130\\ \\y=\dfrac{130}{26}=5.

Now substitute z=2 and y=5 into the first equation:

3x-4\cdot 5-5\cdot 2=-27\\ \\3x-20-10=-27\\ \\3x-30=-27\\ \\3x=-27+30=3\\ \\x=1.

The solution is (1,5,2)

4 0
3 years ago
A. Integer<br><br> B. Rational Number<br><br> C. Natural Number <br><br> D. Irrational Number
Paladinen [302]

Answer:

b

Step-by-step explanation:

b b b b b b b b b b b b b b b b b b b b b b b b

8 0
3 years ago
I need help..........
Marat540 [252]
Answer: 3rd one
Rearrange the original equation so it fits the model of : ax^2+bx+c=0
Then use the quadratic formula to find all possible answers.
5 0
3 years ago
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