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2 years ago

15

Mark’s garden is a rectangle that is meters long and meters wide. If Mark decides to fence his garden, the total length of fe

ncing material required would be meters. If he uses prebuilt fence sections that are 50 centimeters wide, he will need sections.

1 answer:

Fudgin [204]2 years ago

3 0

50cm = 0.5 meters ,so he will need 32 sections

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AABC has vertices at A(1, -9), B(8,0), and C(9,-8).

Rainbow [258]

Check the picture below.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}$

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

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2 years ago

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Eddi Din [679]

Bmrruray is the answer

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2 years ago

Another one that is even more confusing because it is a fraction.

kogti [31]

Answer:

2/16

Step-by-step explanation:

i just doubled he equation

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3 years ago

2/3 5/7 16/21 smalledr to biggedt

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Step-by-step explanation:

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Read 2 more answers

(64x^8– 4x^3 + 24) : (8x^3)

andrey2020 [161]

Answer:

(16 x^8 - x^3 + 6)/(2 x^3)

Step-by-step explanation:

Simplify the following:

(64 x^8 - 4 x^3 + 24)/(8 x^3)

Factor 4 out of 64 x^8 - 4 x^3 + 24:

(4 (16 x^8 - x^3 + 6))/(8 x^3)

4/8 = 4/(4×2) = 1/2:

Answer: (16 x^8 - x^3 + 6)/(2 x^3)

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3 years ago