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Licemer1 [7]
3 years ago
7

Choose the graph of y = 2 cos x

Mathematics
2 answers:
drek231 [11]3 years ago
5 0
Y = cos x begins at (0,1), descends to (pi/2,0), descends to (pi,-1), ascends to (3pi/2,0), and then ascends to (2pi,1).  This covers only one full period.

The graph of y = 2cost x is the same, except that the amplitudes (y-values) are 2x as great as before:

(0,2), (pi/2, 0), and so on.
Butoxors [25]3 years ago
5 0

Answer:

The graph is in the attachment.

Step-by-step explanation:

The cosine function is periodic. This means that every 2pi, the image is the same.

For y = 2 cos x, the amplitude of the function is given by 2.

The domain of the function is (-∞,∞).

The image of the function is [-2, 2].

<u>For example:</u>

y(0) = 2 cos 0 = 2 . 1 = 2.

y(pi/2) = 2 cos(pi/2) = 2 * 0 = 0.

y(pi) = 2 cos(pi) = 2 * -1 = -2.

y(3pi/2) = 2 cos(3pi/2) = 2 * 0 = 0.

y(2pi) = 2 cos(2pi) = 2 * 1 = 2.

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141.75 rounded to the nearest hundredth
muminat

Answer:

141.75

Step-by-step explanation:

Since it is already rounded to the nearest hundredth, you don't need to do anything.

6 0
3 years ago
If √2 = 1.414 then the value of 5+√2 / 5-√2 is
Gala2k [10]

Answer:

1.787

Step-by-step explanation:

\\  \sf \frac{5 +  \sqrt{2} }{5 -  \sqrt{2} }  \times  \frac{5 +  \sqrt{2} }{5  +   \sqrt{2} }

\\   \sf =  \frac{(5 +  \sqrt{2}) }{5 -  \sqrt{2} }  \times  \frac{(5 +  \sqrt{2}) }{5 +  \sqrt{2} }

\\  \sf =  \frac{25 + 5 \sqrt{2 } + 5 \sqrt{2} + 2  }{( {5})^{2}  - ( \sqrt{ {2}})^{2} }

\\  \sf =  \frac{27 + 10 \sqrt{2} }{25 - 2}

\\  \sf =  \frac{27 - 10 \sqrt{2} }{23}

Now putting the value of√2

\\  \sf =  \frac{27 + 10 \times 1.414}{23}

\\  \sf =  \frac{27 + 14.14}{23}

\\  \sf =  \frac{41.14}{23}

\\ \sf = 1.787

3 0
3 years ago
20 POINTS!!!!
Nata [24]

Answer:

0.5+3.7 =4.2

You meant translate into numbers, correct?

5 0
3 years ago
Whats 1 1..........................................?
olasank [31]
<span>It depends on the number system and the defined operation.

In simple addition we get 1+1=2
In group theory, provided a binary operation as addition modulo 2 is defined, we get (1+1) mod 2 = 0
</span>
4 0
4 years ago
Read 2 more answers
Find the equation of the line through point (8, -9) and perpendicular to 3x +8y =4
gregori [183]

Answer:

3y = 8x - 91

y = 8/3 * x - 30 1/3

Step-by-step explanation:

First we can find the slope of the second line.

Let's rewrite the equation as 8y=44-3x.

After dividing both sides of the equation by 8 we'll get an equivalent equation y = 5.5 - 3/8 * x. The coefficient of x is the slope -> the slope is -3/8. In order for the line to be perpendicular to this line the product of the slopes of two lines should be equal to -1 or in other words the slopes have to be opposite reciprocals of each other. The reciprocal of -3/8 is -8/3. Opposite to it is 8/3. Now we know the slop and the coordinates of a point on the line (given). Let's make the equation of the line in the form of y = mx+ b. We can plug in values for m, y and x. m = 8/3(slope), y=-9 (second coordinate of the point), x = 8 (first coordinate). We got

-9 = 8/3 * 8 +b

Now we need to solve the equation to find b

b =-91/3 or -30 1/3

7 0
2 years ago
Read 2 more answers
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