Hey there, the answer is C.
After multiplying, you will get .37278. However, it's asking you to consider the significant figure of 3 so you'll have to round it to .373. C has that only option
Answer:
D corresponds to the base.
Ethire C or A corresponds to the height.
I'm sorry, that's all I know. I'm new to this kind of math.
Step-by-step explanation:
Answer:
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
Step-by-step explanation:
The sample proportion is p2= 7/27= 0.259
and q2= 0.74
The sample size = n= 27
The population proportion = p1= 0.4
q1= 0.6
We formulate the null and alternate hypotheses that the new program is effective
H0: p2> p1 vs Ha: p2 ≤ p1
The test statistic is
z= p2- p1/√ p1q1/n
z= 0.259-0.4/ √0.4*0.6/27
z= -0.141/0.09428
z= -1.496
The significance level ∝ is 0.05
The critical region for one tailed test is z ≤ ± 1.645
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
Answer:
D
Step-by-step explanation:
Given the 2 equations
y = x - 5 → (1)
y = x² - 5x + 3 → (2)
Substitute y = x² - 5x + 3 into (1)
x² - 5x + 3 = x - 5 ← subtract x - 5 from both sides
x² - 6x + 8 = 0 ← in standard form
(x - 2)(x - 4) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 2 = 0 ⇒ x = 2
x - 4 = 0 ⇒ x = 4
Substitute each of these values into (1) for corresponding values of y
x = 2 → y = 2 - 5 = - 3 ⇒ (2, - 3 )
x = 4 → y = 4 - 5 = - 1 ⇒ (4, - 1 )
Answer:
15 hours
Step-by-step explanation:
Given:
Fernell's speed
mph
Dabney's speed
mph
Denote:
- distance covered by Fernell
- distance covered by Dabney
- Fernell's time
- Dabney's time
1. If Fernell drove for 3 hours longer than Dabney, then his time is 3 hours more than Dabney's time and

2. If Fernell covered 18 miles less than Dabney, then

Use formula 

Subtract from the first equation the second equation and equate it to 18:

