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3 years ago

What comes 10,000 before and 10,000 after this number 52,812?

Mathematics

1 answer:

astraxan [27]3 years ago

8 0

42,812 and 62,812! You just add and subtract 10,000 from 52,812 and you will get the answer! Hope this helps!

You might be interested in

Express the following rate as a unit rate. If necessary, round your answer to the nearest tenth. 63 quarts for 56 seconds

gavmur [86]

Answer:

1.1 qt/s

Step-by-step explanation:

To find quarts per second, divide quarts by seconds:

(63 qt)/(56 s) = 9/8 qt/s ≈ 1.1 qt/s

8 0

3 years ago

The number of kilograms of water in a human body varies directly as the mass of the body. A 72 kg person contains 48 kg of water

Tanzania [10]

Step-by-step explanation:

N=km

72=k×48

72=48k

k=72/48

k=1.5

N=1.5m

N=1.5×144

N=216

3 0

2 years ago

In Triangle XYZ, measure of angle X = 49° , XY = 18°, and

marissa [1.9K]

Answer:

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

$YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X$ (1)

If we know that $X = 49^{\circ}$ , $XY = 18$ and $YZ = 14$ , then we have the following second order polynomial:

$14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}$

$XZ^{2}-23.618\cdot XZ +128 = 0$ (2)

By the Quadratic Formula we have the following result:

$XZ \approx 15.193\,\lor\,XZ \approx 8.424$

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

$XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y$

$\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}$

$Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)$

1) $XZ \approx 15.193$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 54.987^{\circ}$

2) $XZ \approx 8.424$

$Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]$

$Y \approx 27.008^{\circ}$

There are two choices for angle Y: $Y \approx 54.987^{\circ}$ for $XZ \approx 15.193$ , $Y \approx 27.008^{\circ}$ for $XZ \approx 8.424$ .

6 0

3 years ago

if the area of a triangular base prism is 11 cm² and the height of the prism is 12 cm, what is the volume of the prism?

Natasha2012 [34]

Answer:

132 cm²

Step-by-step explanation:

Your welcome

7 0

3 years ago

What is the answer to 11/12×6=

Mademuasel [1]

Answer:

$\frac{11}{2}$

Step-by-step explanation:

$\frac{11}{12}$ x 6 = $\frac{11}{2}$

5 0

3 years ago