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Colt1911 [192]
3 years ago
13

Given

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:option 2

Step-by-step explanation:sets Band C contains 2,4,6 in common

Set A and the common set of B and C stated above contains 2 in common

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Graph ​ y&gt;1−3x .​<br><br> Please help
adoni [48]

Answer:

the answer would be letter B

Step-by-step explanation:

7 0
3 years ago
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Milly has a equal number of 20p coins and 50p coins . The value of her 20p coins is £2.80 . Work out the total value of her 20p
Zinaida [17]

Answer:

£9.80

Step-by-step explanation:

The calculation of the total value is given below:

Provided that that

The value of 20p coins is £2.80

So 1p = £2.80 ÷ 20

= £0.14

For 50p it would be

= £0.14 × 50

= £7

Now the total value is

= £2.80 +  £7

= £9.80

3 0
3 years ago
Marking as Brainliest create an x/y chart !
MAVERICK [17]
Mark points (0,0), (-1,-1), (1,-1), (-2,-4), (2,-4)
8 0
3 years ago
Complete the solution of the equation. Find the value of y when x equals -15. -x ‒ 8y = -1
valkas [14]
To complete the solution of - x - 8y = -1, we first need to substitute x for -15.
As so:

-(-15) - 8y = -1
15 - 8y = -1

Next, we can subtract 15 from each side to get:

15 - 15 - 8y = -1 - 15
- 8y = -16

Now, we can divide by -8 on each side to get the y by itself:

-8y / -8 = -16 / -8 
y = -16 / -8
y = 2

There we go! <em>y</em> = 2 when x = -15! Hope I could help you out! Have a good one.
5 0
3 years ago
the length of a rectangle exceeds its width by 6 inches and the area is 40 square inches. What are the length and width of the r
Lorico [155]

Classic Algebra and its unnecessarily complicated sentence structure. As you may have probably known, Algebra has its own "vocabulary set".


"the length of a rectangle exceeds its width by 6 inches" -> length is 6 in. longer than width -> l= w + 6


Since we're solving for the length and width, let's give them each variables.

length = l = w+6

width = w


The next bit of information is "the area is 40 square inches"

Applying the formula for the area of a rectangle we can set up:

l x w = 40

replace "l", or length, with it's alternate value.

(w+6) x w = 40

distribute

w^{2} + 6w = 40

subtract 40 from both sides

w^{2} + 6w - 40 = 0

factor

(w - 4)(w + 10) = 0

solve for w

w= 4, or -10


So great, we have 2 values; which one do we choose? Since this problem is referring to lengths and inches, we will have to choose the positive value. There is not such thing as a negative distance in the real world.


We now have half of the problem solved: width. Now we just need to find the length which we can do but substituting it back into the original alternate value of l.


l = w + 6

w=4

l = 4 + 6 = 10


The length is 10 in. and the width is 4 in. Hope this helps!

8 0
3 years ago
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