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Reptile [31]
3 years ago
7

Suppose that the expected value of a measurement is 17 N.

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0
C ahaha siwvushss sjdjshsgau avians
iragen [17]3 years ago
4 0

Answer:

Jaga Raga OI roti caita C

Explanation:

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Sindrei [870]
We can explain this in a molecular level. We know that the difference between a gas and a liquid of the same composition is how fast their molecules are moving. So given a gas, their molecules are farther and faster when moving, but when they are cooled their bulk kinetic energy decreases. In other words their molecules start to move closer and move slower until it behaves more like a liquid molecule. This is the time when gases condense. 
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3 years ago
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Down a group, the electron shielding tends to________
JulsSmile [24]

Answer:

A

Explanation The number of energy levels (n) increases, and so does the distance between the nucleus and the outermost orbital. The increased distance and the increased shielding weaken the nuclear attraction, and so an atom can't attract electrons as strongly.

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In which of these situations is convection most likely the main form of heat transfer?
lorasvet [3.4K]
In the first situation: the mechanism of covection is the main form of heat transfer when warm air from a heater moves around and upward.

In the case of the metal pan the mechanism of heat transfer is conduction.

In the case of sunburn the mechanism is radiation.

In the case of an ice cube melting in a hand, conduction is the most important mechanism.
5 0
3 years ago
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How many milliliters of a 3.0 M HCL solution are required to make 250.0 millimeters of 1.2 M HCL?
White raven [17]
The problem above can be solved using M1V1=M2V2  where M1 is the concentration of the concentrated, V1 is the volume of the concentrated solution, M2 is the concentration of the Dilute Solution, V2 is the Volume of the dilute solution. Hence,

(3.0 M)(V2)=(250 mL)(1.2M)
V2 (3.0)= 300
V2= 100 mL

Therefore, you need 100 mL of 3.0 M HCl to form a 250 mL of 1.2 M HCl.
7 0
3 years ago
Classify..use the periodic table to classify the elements potassium, bromine a d argon according to how likely their atoms lose
iren2701 [21]

Answer:

Classification will be Potassium, Bromine, and Argon

Explanation:

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6 0
3 years ago
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