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Nonamiya [84]
4 years ago
9

Each enzyme has an optimal temperature and pH that it works best in. If enzyme ABC works best at pH 7, but ABC is in a cell with

a pH of 9, will it catalyze more or less reactions?
Chemistry
1 answer:
xeze [42]4 years ago
3 0

Answer:

Less reactions because it does not have the best pH to for that particular enzyme to work in. If it was at pH of 7, ABC would work best and catalyze a lot of reactions, but since the pH is 9 it will not work as efficiently or better so it will catalyze less reactions.

Explanation:

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MERCURY
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4 0
3 years ago
Read 2 more answers
PLEASE HELP WILL GIVE BRAINLIEST...
mestny [16]

Answer:

Y³⁻  A non metal that gained three electrons.

V²⁺ A metal that lost two electron

Z²⁻ A non metal that gained two electrons

X³⁺ A metal that lost three electrons

Explanation:

Metals lost the electrons and form cation

while non metals gain the electrons and form anion.

Y³⁻

c) A non metal that gained three electrons.

Non metal gain three electrons and form anion with the charge of -3.

V²⁺

a) A metal that lost two electron

A metal lost two electrons and form cation with charge of +2.

Z²⁻

d) A non metal that gained two electrons

A non metal that gained two electrons and form anion with charge of -2.

X³⁺

b) A metal that lost three electrons

A metal that lost three electrons and form cation with charge of +3.

4 0
3 years ago
Crude oil can be separated into its consistent parts based on their boiling points. What technique uses this principle?
omeli [17]
The answer is B, distillation.

(You can see more details about distillation as well as other separation techniques on the document pdf titled Lab #2 Physical Separation Techniques by ccri.edu)
6 0
3 years ago
Read 2 more answers
Group VII corresponds to the...
SCORPION-xisa [38]

Answer:

Halogens family

Explanation:

Be familiar with the periodic table

5 0
4 years ago
Read 2 more answers
If 255 g of water has 10.0 g of NaCl dissolved into initially, how much NaCl must be added in order to raise the mass percent of
Ipatiy [6.2K]
M(H₂O) = 255 g.
m₁(NaCl) = 10.0 g.
m₁(solution) = 255 g + 10 g = 265 g.
ω₁ = 10 g / 265 g · 100%.
ω₁ = 3.77% ÷ 100% = 0.0377.
ω₂= 10% ÷ 100% = 0.1.
ω₂= m₁(NaCl) + m₂(NaCl) / m₁(solution) + m₂(NaCl).
0.1 = 10 g + m₂(NaCl) / 265 g + m₂(NaCl).
26.5 g + 0.1·m₂(NaCl) = 10 g + m₂(NaCl).
0.9·m₂(NaCl) = 16.5 g.
m₂(NaCl) = 18.33 g.
8 0
3 years ago
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