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3 years ago

How many milliliters are in 8.12 moles of N2

Chemistry

1 answer:

maksim [4K]3 years ago

7 0

Answer:

1.2506 g/L is the density of N2

8.12 moles x 28g/mole = 227.36 g

227.36 g x L/1.2506 = 181.888 L (1000ml/L)= 181,888 ml

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anuvia, the trade name for sitagliptin, was introduced in 2006 for the treatment of type 2 diabetes. In what type of orbital doe

Aleonysh [2.5K]

Answer: hello your question is poorly written below is the complete question

answer:

For N1 : sp³ orbital

For N2: p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

Explanation:

Determining the type of orbital in which the lone pair on each N atom will reside.

From the configuration attached below we can determine the type of orbital and they are ;

For N1 : sp³ orbital

For N2: p orbital

For N3 : p orbital

For N4 : sp² orbital

For N5 : sp² orbital

5 0

3 years ago

How would you prepare 175 mL of a 0.350kmol/m^3 calcium nitrate solution

SVEN [57.7K]

0,35 kmol/m³ = 0,35 mol/dm³ = 0,35 mol/L
175 mL = 0,175 L
*-*-*-*-*-*-*-*-*-*-*-*
C = n/V
n = 0,35×0,175
n = 0,06125 mol

mCa(NO₃)₂: 40+(14×2)+(16×6) = 164 g/mol

1 mol --------- 164g
0,06125 ---- X
X = 10,045g

To prepare 175 mL of 0,35M solution, add 10,045g of calcium nitrate and add water to a volume of 175ml.

3 0

3 years ago

Iron forms rust, expressed as Fe2O3.

Elina [12.6K]

Answer:

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Explanation:

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3 years ago

Suppose 215 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?

charle [14.2K]

Answer:

The answer is " $41.23 \ L\ N_2$ "

Explanation:

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3 years ago

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gogolik [260]

Answer:

It's obviously true

Explanation:

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3 years ago